I need help with 8a please

Min-Jee is planting two rectangular flower beds. One bed is 2.78 feet by 4.81 feet, and the other bed is 2.78 feet by 5.61 feet.

shusha [124]

Answer: $(2.78+4.81)(2.78+5.61)$

Step-by-step explanation:

<h3> The complete exercise is attached.</h3><h3></h3>

The area of a rectangle can be calculated with this formula:

$A=lw$

Where "l" is the lenght and "w" is the width.

Then, you can notice that it can be obtained by multiplying the dimensions of the rectangle.

Knowing this, you can determine that the total area of the two flowers bed can be obtained by adding the products of their dimensions.

Since one of the rectangular flower bed is 2.78 feet by 4.81 feet and the other bed 2.78 feet by 5.61 feet, you can write the following expression to find the total area (in square feet)of the two beds:

$2.78*4.81 +2.78*5.61$

If you factor out 2.78:

$2.78(4.81 +5.61)$ or $(4.81 +5.61)2.78$

Therefore, the expression that does not represent the total area in square feet of the two beds, is:

$(2.78+4.81)(2.78+5.61)$

6 0

3 years ago

Read 2 more answers

What is 3.1666666667 as a fraction

never [62]

7 0

3 years ago

Please help.<br> Is algebra.

Dvinal [7]

Answers:

Blank 1: 4
Blank 2: -1

So the solution is (x,y) = (4, -1)

=============================================================

Work Shown:

6x + 7y = 17

6x + 7( y ) = 17

6x + 7( -3x+11 ) = 17 ... replace every copy of y with -3x+11

6x - 21x + 77 = 17

-15x = 17-77

-15x = -60

x = -60/(-15)

x = 4

We'll use this x value to find y

y = -3x+11

y = -3(4)+11 ... replace x with 4

y = -12+11

y = -1

We have x = 4 and y = -1 pair up together to give us the solution (x,y) = (4, -1)

------------------------

To check the solution, we plug x = 4 and y = -1 into each equation

Plugging the values into the first equation leads to...

y = -3x+11

-1 = -3(4)+11

-1 = -1

This is effectively already done in the last part of the previous section. But it doesn't hurt to verify like this regardless.

We'll need to verify the second equation as well.

6x + 7y = 17

6(4) + 7(-1) = 17

24 - 7 = 17

17 = 17

We get a true equation, so the solution is confirmed with both equations. Overall, the solution to the system of equations is confirmed. This system is independent and consistent.

3 0

3 years ago

Hi guys, can anyone help me with this triple integral? Many thanks:)

Crank

Another triple integral. We're integrating over the interior of the sphere

$x^2+y^2+z^2=2^2$

Let's do the outer integral over z. z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

$y^2=4-x^2-z^2$

x is the inner integral so at this point we conservatively say its zero. That means y goes from $-\sqrt{4-z^2}$ and $+\sqrt{4-z^2}$

Similarly the inner integral x goes between $\pm-\sqrt{4-y^2-z^2}$

So we rewrite the integral

$\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz$

Let's work on the inner one,

$\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz$

There's no z in the integrand, so we treat it as a constant.

$=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}$

So the middle integral is

$\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy$

I gotta go so I'll stop here, sorry.

7 0

3 years ago

Read 2 more answers

Event the die comes up at most 2

hjlf

X. 1. 2. 3. 4. 5. 6 are all the possible events when rolling a die. If it is a fair die then the probability of rolling any number is 1/6. So the probability of rolling at most a two is p(1)+ p(2)= 2/6 or 1/3

4 0

4 years ago