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Vladimir79 [104]
4 years ago
14

Pam bought 50 kg of sugar. She used 10 kg of sugar. What percentage of sugar was left? (step by step answer would be appreciated

)
Mathematics
2 answers:
galben [10]4 years ago
8 0

Answer:

80%

Step-by-step explanation:

50 x 50 would be 100 and 50kg=100% and 10 x 2 = 20 so you used 20% therefore you have 80% left.

USPshnik [31]4 years ago
4 0

Answer:

80% of sugar left.

Step-by-step explanation:

If we start of with 50 kg of sugar and we take away 10 kg of sugar, we are left with 50-10=40 kg of sugar.

To find the percentage of sugar left, we divide the decreased number by the original number.

\frac{40}{50} = \frac{4}{5} = 0.8

If we have a decimal and want to convert it to a percentage, we multiply it by 100.

0.8\cdot100=80

So, 80% of the sugar is left.

Hope this helped!

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The volume of a number cube is 27 cm^3. What is the length of each side of a cube?
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Answer:

54

Step-by-step explanation:

Since it's a "cube", all sides must be equal. Therefore, the length of one side is equal to the cube root of the volume.

3√27=3

An area of one surface is equal to

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Since the area of all surfaces are equal, we can assume that the surface area of this cube is

9⋅6

, because there are 6 surfaces on a cube

9⋅6=54

Hope this helps.

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The Half-life of a certain substance is 20 mins. You start with 45 mg of the substance
DochEvi [55]

a. Remaining amount after t minutes = 45 * (1/2)^{\frac{t}{20 }

b.  0.010986 mg

c. 109.84 minutes

Step-by-step explanation:

Step 1:

The decay of the substance is exponential. It is given that half life is 20 minutes and initially we start with 45 mg. So in 20 minutes we will have remaining amount 45/2, in 40 minutes remaining amount will be 45/4 etc.

This can be modeled by the equation:

Remaining amount after t minutes = Original amount * (1/2)^{\frac{t}{t_{1/2}  }

where  t_{\frac{1}{2}} represents the half life.

The half life for this substance is 20 minutes.

Hence the Remaining amount after t minutes = 45 * (1/2)^{\frac{t}{20 }

Step 2:

We need to calculate the amount remaining after 4 hours (240 minutes).

Substituting t = 240 in above equation we get

Amount remaining after 4 hours = 45 * (1/2)^{\frac{240}{20 } = 0.010986 mg

Step 3:

We need to calculate the time taken when 1 milligram is left. Substituting in the equation we get

1 = 45 * (1/2)^{\frac{t}{20 }  

Taking log on both sides we get

t = \frac{20 ln (1/45)}{ln 1/2} = 109.84 minutes

Time taken for 1 mg of the substance to be left = 109.84 minutes

Step 4 :

Answer :

a. Remaining amount after t minutes = 45 * (1/2)^{\frac{t}{20 }

b.  0.010986 mg

c. 109.84 minutes

7 0
4 years ago
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