Answer:
Probability that a smoker has lung disease = 0.2132
Step-by-step explanation:
Let L = event that % of population having lung disease, P(L) = 0.07
So,% of population not having lung disease, P(L') = 1 - P(L) = 1 - 0.07 = 0.93
S = event that person is smoker
% of population that are smokers given they are having lung disease, P(S/L) = 0.90
% of population that are smokers given they are not having lung disease, P(S/L') = 0.25
We know that, conditional probability formula is given by;
P(S/L) =
= P(S/L) * P(L)
= 0.90 * 0.07 = 0.063
So,
= 0.063 .
Now, probability that a smoker has lung disease is given by = P(L/S)
P(L/S) =
P(S) = P(S/L) * P(L) + P(S/L') * P(L')
= 0.90 * 0.07 + 0.25 * 0.93 = 0.2955
Therefore, P(L/S) =
= 0.2132
Hence, probability that a smoker has lung disease is 0.2132 .
Ermm, Don't you think it's 60?
Cause in my caculatons it's 60
The rule of the function is to multiply the input by 3, since one yard is equal in length to three feet.
So, if the input is 15.4, the output will be
![f(x)=3x \implies f(15.4)=3\cdot 15.4 = 46.2](https://tex.z-dn.net/?f=f%28x%29%3D3x%20%5Cimplies%20f%2815.4%29%3D3%5Ccdot%2015.4%20%3D%2046.2)
Hey there!
![20*pi/360=4*pi/x solve for x x=360*4*pi/(20*pi)=72 degrees](https://tex.z-dn.net/?f=20%2Api%2F360%3D4%2Api%2Fx%20solve%20for%20x%20x%3D360%2A4%2Api%2F%2820%2Api%29%3D72%20degrees)
Your correct answer would be
. . .
![\boxed{\boxed{72}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B72%7D%7D)
Hope this helps.
~Jurgen
Answer:
50 students
Step-by-step explanation:
Hello!
To solve this question, we would first need to look at the data. In this data, there are people who chose their favorite sport, and the number of people who chose that response. In order to solve the problem, we would have to find the ratio of how many people choose baseball over the other sports.
By this, we can add the number of students together. 30+10+5+15=60. Out of those 60 students, only 5 people chose baseball.
Since the ratio of the people who chose baseball is 5/60 (meaning that it is a 5/60 % chance someone would pick this sport), we would need to find the amount of people assumed to pick baseball in 600 student survey.
We can make a relationship with these two numbers.
, since the ratio of the students who chose baseball remain the same.
You can see that the ratio on the denominators just add a zero on the bottom, so the top should add 0 as well, to get 50 for x, what we needed.
You can also solve that relationship by cross multiplication.
5(600)=x(60
3000=60x
50=x
Regardless, the answer is 50 students who would choose baseball in a 600 persons survey.