Did the maya create chocolate

Is 1/10 greater then or less then 0.09

nikdorinn [45]

0.10 > 0.09 It is greater than.

6 0

3 years ago

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Which answer best explains theoretical and experimental probability?

Harman [31]

Answer:

......The answer is C..............

7 0

2 years ago

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Jordan invests £17200 into his bank account.

timurjin [86]

Hope this will help u...

3 0

2 years ago

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Pam has 90 m of fencing to enclose an area in a petting zoo with two dividers to separate three types of young animals. The thre

andrew-mc [135]

Answer:

The area function is

$A=\frac{135}{2}x-\frac{9}{2}x^2$ .

The domain and range of A is $(0,15m)$ and $(0, 253.125 m^2]$ .

Step-by-step explanation:

The given length of fencing is $90 m$ .

Let the length and width of each pen be $x$ and $y$ respectively as shown in the figure.

As there are 3 pens, so, the total area,

$A= 3 xy \;\cdots (i)$

From the figure the total length of fencing is $6x+4y$ .

Here, for a significant area for the animals, $x>0$ as well as $y>0$ as $x$ and $y$ are the sides of ben.

From the given value:

$6x+4y=90\;\cdots (ii)$

$\Rightarrow y=\frac {45}{2}-\frac{3x}{2}$

Now, from equation (i)

$A=3x\left(\frac {45}{2}-\frac{3x}{2}\right)$

$\Rightarrow A=\frac{135}{2}x-\frac{9}{2}x^2\;\cdots (iii)$

This is the required area function in the terms of variable $x$ .

For the domain of area function, from equation (ii)

$x=15-\frac{2y}{3}$

$\Rightarrow x$ [as y>0]

So, the domain of area function is $(0,15m)$ .

For the range of area function:

As $x \rightarrow 0$ or $y\rightarrow 0$ , then $A\rightarrow 0$ [from equation (i)]

$\Rightarrow A>0$

Now, differentiate the area function with respect to $x$ .

$\frac {dA}{dx}=\frac{135}{2}-9x$

Equate $\frac {dA}{dx}$ to zero to get the extremum point.

$\frac {dA}{dx}=0$

$\Rightarrow \frac{135}{2}-9x=0$

$\Rightarrow x=\frac{15}{2}$

Check this point by double differentiation

$\frac {d^2A}{dx^2}=-9$

As, $\frac {d^2A}{dx^2}$ , so, point $x=\frac{15}{2}$ is corresponding to maxima.

Put this value back to equation (iii) to get the maximum value of area function. We have

$A=\frac{135}{2}\times \frac {15}{2}-\frac{9}{2}\times \left(\frac {15}{2}\right)^2$

$\Rightarrow A=253.125 m^2$

Hence, the range of area function is $(0, 253.125 m^2]$ .

4 0

3 years ago

Select "Yes" or "No" to indicate whether the ordered pair is on the graph of the function f(x)=−25^x+1.

KengaRu [80]

(1,625) No (0,-25) No (-1,-1) No Think about what an integer exponent means for an negative base and you'll understand this problem. For instance the powers of -25 would be -25^1 = -25 -25^2 = (-25) * (-25) = 625 -25^3 = (-25)*(-25)*(-25) = -15625 and so on, giving 390625, -9765625, 244140625, etc. But that's a different subject. For the ordered pairs given, let's check them out. (1,625) -25^1 + 1 = -25 + 1 = -24. And -24 is not equal to 625, so "No". (0,-25) -25^0 + 1 = 1 +1 = 2. Note: Any real number other than 0 raised to the 0th power is 1. And 2 is not equal to -25, so "No". (-1,-1) -25^(-1) + 1 = 1/(-25^1) + 1 = 1/-25 + 1 = 24/25. And 24/25 is not equal to -1, so also "No".

3 0

3 years ago

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