All categories

3 years ago

Which relationship describes angles 1 and 2?

Mathematics

1 answer:

VladimirAG [237]3 years ago

3 0

They are complementary angles and they are adjacent angles to

You might be interested in

Help solving this math

Anna [14]

-3.6
Explaination: it goes through the 6 and -3 points in the slope.

4 0

3 years ago

Read 2 more answers

4x-y=10 and y=2x-2 answers

Brums [2.3K]

4x - y = 10, y = 2x - 2

4x - (2x -2) = 10

4x - 2x + 2 = 10

2x = 8

x = 4

4(4) - y = 10

-y = -6

y = 6

So x = 4 y= 6

Hope this helps!
Brainliest and a like is much appreciated!

6 0

3 years ago

Read 2 more answers

I wanna know if any of you guys could possibly help me with my foods work? It’s not hard it’s just a lot of once and I really ha

vladimir1956 [14]

What is it about. I think I can help you just got to explain what you need to do

3 0

3 years ago

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

Multiplying both sides by 16 we get:

$256=3x^2$

Dividing both sides by 3 we get:

$\frac{256}{3} =x^2$

Using square root on both sides we get:

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

So, the base of triangle = $\frac{8}{\sqrt{3}} \ m.$

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

Thus, the height of triangle = $\frac{12}{\sqrt{3}} \ m.$

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

7 0

3 years ago

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

dalvyx [7]

Answer:

The answer would be: D. (1,2) and (2,-1)

5 0

3 years ago

Read 2 more answers