Answer:
$29,900
Growth
22%
Step-by-step explanation:
Initial value is when t = 0
v(0) = 29900(1.22)^0
v(0) = 29900(1)
v(0) = 29900
-------------------------
Growth
because 1.22 is greater than 1
----------------------------
Yearly value change
1.22 - 1 = 0.22
0.22 * 100 = 22
22%
I am certain the answer is C. Algebra properties are used in proofs. Postulates are definitely used. And definitions are explanations. So, it is C.
Answer:
Company one charges $11 + $0.16 per min.
Then if you talk for x minutes, the cost will be:
C₁(x) = $11 + ($0.16 per min)*x
For company two, the prize is $20 + $0.11 per min, and if yo talk for x minutes, the cost will be:
C₂(x) = $20 + ($0.11 per min)*x
Now we want to find the value of x, the number of minutes, such that the cost is the same with both companies.
C₁(x) = C₂(x)
$11 + ($0.16 per min)*x = $20 + ($0.11 per min)*x
($0.16 per min)*x - ($0.11 per min)*x = $20 - $11
($0.05 per min)*x = $9
x = $9/($0.05 per min) = 180 mins
If you speak for 180 minutes, the cost is the same in both companies.
It would be a straight line
Xy = 6
x = 2
2y = 6
y = 6÷2
y = 3
x + y = (2) + (3) = 5
