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kirill115 [55]
2 years ago
15

Can someone PLEASE help me solve these last 2 problems so I can be done with this math class....really stumped on these 2....

Mathematics
1 answer:
dexar [7]2 years ago
3 0
Both distances 3966 and 4746 were done in 6 hours, so the speeds are:
speed against wind = 3966/6=661 km/h (difference of airplane and wind)
speed with wind = 4746/6=791 km/h (sum of airplane and wind)

The speed of airplane is greater than that of the wind, so this is a sum and difference problem.

Greater speed (plane) = (sum+difference)/2=(791+661)/2=726 km/h
Lesser speed (wind) = (sum-difference)/2 = (791-661)/2 = 65 km/h

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antiseptic1488 [7]
-\dfrac{1}{2}(-4+2x)=-6-4x\ \ \ \ \ |multiply\ both\ sides\ by\ (-2)\\\\-4+2x=12+8x\ \ \ \ |add\ 4\ to\ both\ sides\\\\2x=16+8x\ \ \ \ \ |subtract\ 8x\ from\ both\ sides\\\\-6x=16\ \ \ \ \ |divide\ both\ sides\ by\ (-6)\\\\x=-\dfrac{16}{6}\\\\x=-\dfrac{8}{3}\\\\\boxed{x=-2\frac{2}{3}}
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3 years ago
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