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2 years ago

15

Can someone PLEASE help me solve these last 2 problems so I can be done with this math class....really stumped on these 2....

1 answer:

dexar [7]2 years ago

3 0

Both distances 3966 and 4746 were done in 6 hours, so the speeds are:
speed against wind = 3966/6=661 km/h (difference of airplane and wind)
speed with wind = 4746/6=791 km/h (sum of airplane and wind)

The speed of airplane is greater than that of the wind, so this is a sum and difference problem.

Greater speed (plane) = (sum+difference)/2=(791+661)/2=726 km/h
Lesser speed (wind) = (sum-difference)/2 = (791-661)/2 = 65 km/h

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