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kirill115 [55]
3 years ago
15

Can someone PLEASE help me solve these last 2 problems so I can be done with this math class....really stumped on these 2....

Mathematics
1 answer:
dexar [7]3 years ago
3 0
Both distances 3966 and 4746 were done in 6 hours, so the speeds are:
speed against wind = 3966/6=661 km/h (difference of airplane and wind)
speed with wind = 4746/6=791 km/h (sum of airplane and wind)

The speed of airplane is greater than that of the wind, so this is a sum and difference problem.

Greater speed (plane) = (sum+difference)/2=(791+661)/2=726 km/h
Lesser speed (wind) = (sum-difference)/2 = (791-661)/2 = 65 km/h

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Suppose that 10% of all homeowners in an earthquake-prone area of California are insured against earthquake damage. Four homeown
guapka [62]

Remainder of question:

Find the probability distribution of x

Answer:

The random variable x is defined as: X = {0, 1, 2, 3, 4}

The probability distribution of X:

P(X = 0) = 0.656

P(X = 1) = 0.2916

P(X= 2) = 0.0486

P(X=3) = 0.0036

P(X = 4) = 0.0001

Step-by-step explanation:

Sample size, n = 4

Random variable, X = {0, 1, 2, 3, 4}

10% (0.1) of the homeowners are insured against earthquake, p = 0.1

Proportion of homeowners who are not insured against earthquake, q = 1 - 0.1

q = 0.9

Probability distribution of x,

P(X = r) = ^nC_r *p^r q^{n-r} \\\\P(X= 0) =(^4C_0 *p^1 q^4 )\\P(X=0) = (^4C_0 *0.1^0 0.9^4 ) = 0.656\\P(X= 1)= (^4C_1 *p^1 q^3 )\\P(X=1) = (^4C_1 *0.1^1 0.9^3 ) = 0.2916\\P(X= 2)=( ^4C_2 *p^2 q^2) \\P(X=2) = (^4C_2 *0.1^2 0.9^2 ) = 0.0486\\P(X= 3) = (^4C_3 *p^3 q^3) \\ P(X=3) = (^4C_3 *0.1^3 0.9^1 ) = 0.0036\\P(X= 4) =  (^4C_4 *p^4 q^0 )\\ P(X=4) =(^4C_4 *0.1^4 0.9^0 ) = 0.0001

5 0
3 years ago
The length of a rectangle is 5.5 feet. If the area is 44 square feet, what is the width of the rectangle, in feet?
vlabodo [156]
So area is length times width therefore
A=LW
44ft^2=5.5W
divide both sides by 5.5
44/5.5=Width=8 feet
7 0
3 years ago
Read 2 more answers
An observer stands 25 feet from the base of a flagpole and watches a flag being lowered at a rate of 5 ft/sec. Determine the rat
Sedaia [141]

Answer:

0.1 rad/s

Step-by-step explanation:

Since the distance from or to the flagpole is not given, I will assume. And my assumption is 50 ft

Now, the elevation angle A = 45 degrees, converting to radians, we have π/4 radians

Remember that the tan of an angle is OPP/HYP, and so

tan A = h/25, on differentiating, we have

d tan A/dA = sec^2 A = (1/25) dh/dA

Next, we have

25 sec^2 A * dA/dt= dh/dt = 5

Making dA/dt the subject of formula, we have

dA/dt = (1/5) cos^2 A

but cos^2 A from trigonometry = 1/2, this means that

dA/dt = .1 radians/second

If you want to convert to degrees, your have

.1 Rad/s( 180 deg/rad) = 18 degrees/second

3 0
3 years ago
Plz guys help me In 2 please
Doss [256]

Answer:

Step-by-step explanation:

OMG!!!!! why don't you just SAY YOU WANT a BLEEPING  REFLECTION!!!

I had to search through a slew of your questions to get clues as to what to do.

To reflect over the x axis, just negate the y term and leave the x term as it is.

M becomes (2, -1)

N becomes (-3, -1)

P becomes (-1, -4)

7 0
3 years ago
Which of the following equations would not be a line when graphed? Explain how you can tell by just looking at the equations.
zlopas [31]
Y=2/x. this equation has degree -1 whereas linear functions have degree 1

y=6x²-7 is nonlinear as it is degree 2
5 0
3 years ago
Read 2 more answers
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