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vitfil [10]
3 years ago
13

Kate has two lengths of ribbon. the pink ribbon is 4 6/12 feet long, and the purple ribbon is 2 4/12 feet long. how much ribbon

does kate have in all?
Mathematics
1 answer:
Vlad1618 [11]3 years ago
4 0
Data:
<span>Kate has two lengths of ribbon
pink ribbon = </span>4 \frac{6}{12} \;feet
purple ribbon = 2 \frac{4}{12} \;feet

<span>How much ribbon does kate have in all?
pink ribbon + purple ribbon

Solving:
</span>4\frac{6}{12} + 2\frac{4}{12} =  \frac{12*4+6}{12} + \frac{12*2+4}{12} =  \frac{48+6}{12} + \frac{24+4}{12} =  \frac{54}{12} + \frac{28}{12} =  \frac{82}{12} =
\frac{82}{12} \:simplify\: \frac{\div2}{\div2} =  \boxed{\boxed{\frac{41}{6} \:or\:6 \frac{5}{6} }}\end{array}}\qquad\quad\checkmark
<span>
Answer:
</span><span>Kate has it all </span>6 \frac{5}{6} of ribbons
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9. An angle is 9 less than twice its supplement. Find the measure of the supplement.​
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The measure of the supplement angle is 63°

Step-by-step explanation:

If two angles are supplementary then the sum of their measures is 180°

The given is:

  • Two supplementary angles
  • One of them is 9 less than twice its supplement

We need to find the measure of the supplement

∵ The two angles are supplementary

∴ The sum of their measure is 180°

Assume that the measure of the supplement angle is x°

∵ An angle is 9 less than twice its supplement

- twice means times 2 and 9 less means subtract 9

∵ The measure of the supplement is x°

∴ The measure of the angle = (2x - 9)°

∵ The sume of the measures of the two angles = 180°

∴ (2x - 9)° + x° = 180°

- Add like terms

∴ (2x + x) - 9 = 180

∴ 3x - 9 = 180

- Add 9 to both sides

∴ 3x = 189

- Divide both sides by 3

∴ x = 63°

The measure of the supplement angle is 63°

Learn more:

You can learn more about supplementary angles in brainly.com/question/11175936

#LearnwithBrainly

5 0
3 years ago
Log1/2 28? What is it?
I am Lyosha [343]
\log_a(b\cdot c)=\log_ab+\log_ac\\\\\log_ab^c=c\cdot\log_ab\\\\\log_aa=1\\--------------------\\\log_\frac{1}{2}28=\log_\frac{1}{2}(4\cdot7)=\log_\frac{1}{2}4+\log_\frac{1}{2}7=\log_\frac{1}{2}2^2+\log_\frac{1}{2}7\\\\=2\log_\frac{1}{2}2+\log_\frac{1}{2}7=\boxed{2+\log_\frac{1}{2}7}


\log_ab=\frac{\log_cb}{\log_ca}\\-------------------------\\\log_\frac{1}{2}7=\frac{\log\frac{1}{2}}{\log7}\approx\frac{-0.6931}{1.9459}\approx-0.3562\\\\therefore\\\\\boxed{\log_\frac{1}{2}28\approx2+(-0.3562)=1.6438}
3 0
3 years ago
The data set below shows prices for concert tickets in 10 major cities. Find the interquartile range​ (IQR) of the set. How do t
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Answer: IQR = 16

Step-by-step explanation:

Given the following data:

Cost of concert :

CITY : Q, R, S, T, U, V, W, X, Y, Z

Price : 35,36,42,38, 24,29,25, 44,49, 26

Interquartile range (IQR) = Q3 - Q1

Where,

Q3 = the upper quartile

Q1 = lower quartile

Rearranging the data:

24,25,26,29,35,36,38,42,44,49

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Answer:

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