Answer:
Heads - Heads - Heads
Tails - Tails - Tails
Heads - Heads - Tails
Heads - Tails - Heads
Heads - Tails - Tails
Tails - Heads - Heads
Tails - Heads - Tails
Tails - Tails - Heads
Step-by-step explanation:
Answer: I believe this is correct, i got 80 tickets
Step-by-step explanation:
I divided 2212.50 by the adult tickets, 7.50, and got 295. if the adults sold 295 tickets, then the students would have sold 80, because thats all that were left. I hope I helped
Answer:
12 people.
Step-by-step explanation:
Let's do this one at a time.
First stop:
0 + 11 = 11
Second stop:
11 + 5 = 16.
16 - 7 = 9.
Third stop:
9 + 5 = 14.
14 - 2 = 12.
<em>There</em><em> </em><em>were</em><em> </em><em>12</em><em> </em><em>people</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>bus</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>driver</em><em> </em><em>left</em><em> </em><em>the</em><em> </em><em>third</em><em> </em><em>stop</em><em>.</em>
Answer:
The answers are 0, 1 and −2.
Step-by-step explanation:
Let α=arctan(2tan2x) and β=arcsin(3sin2x5+4cos2x).
sinβ2tanβ21+tan2β2tanβ21+tan2β23tanxtan2β2−(9+tan2x)tanβ2+3tanx(3tanβ2−tanx)(tanβ2tanx−3)tanβ2=3sin2x5+4cos2x=3(2tanx1+tan2x)5+4(1−tan2x1+tan2x)=3tanx9+tan2x=0=0=13tanxor3tanx
Note that x=α−12β.
tanx=tan(α−12β)=tanα−tanβ21+tanαtanβ2=2tan2x−13tanx1+2tan2x(13tanx)or2tan2x−3tanx1+2tan2x(3tanx)=tanx(6tanx−1)3+2tan3xor2tan3x−3tanx(1+6tanx)
So we have tanx=0, tan3x−3tanx+2=0 or 4tan3x+tan2x+3=0.
Solving, we have tanx=0, 1, −1 or −2.
Note that −1 should be rejected.
tanx=−1 is corresponding to tanβ2=3tanx. So tanβ2=−3, which is impossible as β∈[−π2,π2].
The answers are 0, 1 and −2.
Answer:
c
Step-by-step explanation: