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LUCKY_DIMON [66]

3 years ago

13

A box of 20 dvds is worth $240.00 the box contains some DVDs worth $12.00 each and some DVDs worth 16.00 each. Which system of e

quations can be used to determine x, the number of $12.00 DVDs and y the number of $16.00 DVDs?

1 answer:

Advocard [28]3 years ago

8 0

Answer:

B.

Step-by-step explanation:

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Oblicz.Pamiętaj o kolejności wykonywania działań

SashulF [63]

Answer:

33.275

Step-by-step explanation:

<u>1 step:</u> Difference in brackets

$3.5-2\dfrac{1}{3}=3\dfrac{1}{2}-2\dfrac{1}{3}=(3-2)+\left(\dfrac{1}{2}-\dfrac{1}{3}\right)=1+\dfrac{3-2}{3\cdot 2}=1+\dfrac{1}{6}=1\dfrac{1}{6}$

<u>2 step:</u> $0.75\div\dfrac{1}{3}$

$0.75\div\dfrac{1}{3}=\dfrac{75}{100}\div \dfrac{1}{3}=\dfrac{3}{4}\times \dfrac{3}{1}=\dfrac{9}{4}$

<u>3 step:</u> $1.28\div 0.04$

$1.28\div 0.04=128\div 4=32 \ \text{Move point two decimal places}$

<u>4 step:</u>

$2\dfrac{1}{4}\times 1\dfrac{1}{6}=\dfrac{2\cdot 4+1}{4}\times \dfrac{1\cdot 6+1}{6}=\dfrac{9}{4}\times \dfrac{7}{6}=\dfrac{63}{24}=\dfrac{21}{8}$

<u>5 step:</u>

$\dfrac{9}{4}+32-\dfrac{21}{8}+1.65=(32+1.65)+\left(\dfrac{9}{4}-\dfrac{21}{8}\right)=33.65+\dfrac{9\cdot 2-21}{8}=33.65-\dfrac{3}{8}=33.65-0.375=33.275$

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