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m_a_m_a [10]
3 years ago
13

Identify whether the relationship between ∠a and ∠b in the image below is complementary, linear pair/supplementary, or vertical.

Mathematics
2 answers:
il63 [147K]3 years ago
8 0

Answer:

complementary

Step-by-step explanation:

to complete 90 gradus

Flura [38]3 years ago
3 0

<em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em>

<em>Hey</em><em>!</em><em>!</em>

<em><</em><em>a</em><em> </em><em>and</em><em> </em><em><</em><em>b</em><em> </em><em>are</em><em> </em><em>complem</em><em>entary</em><em> </em><em>angles</em><em>.</em>

<h3><em>Complement</em><em>ary</em><em> </em><em>angles</em><em> </em><em>are</em><em> </em><em>those</em><em> </em><em>a</em><em>n</em><em>g</em><em>l</em><em>e</em><em>s</em><em> </em><em>which</em><em> </em><em>are</em><em> </em><em>e</em><em>xactly</em><em> </em><em>90</em><em> </em><em>degree</em><em>.</em></h3>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

<em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em>

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Solve by graphing <br><br> u=v and 6u=2v-24
Vadim26 [7]

Answer:

u=-6 \\ \\ v=-6

Step-by-step explanation:

In this exercise, we have two equations, namely:

u=v \ and \ 6u=2v-24

And we are asked to solve this problem by graphing. In this way, we can write a system of linear equations in two variables, but first of all, let's rewrite:

u=y \\ \\ v=x

Then:

\left\{ \begin{array}{c}y=x\\6y=2x-24\end{array}\right.

So here we have two lines.

The first one is:

\boxed{y=x}

This line passes through the origin and has a slope m=1

The second one is:

6y=2x-24 \\ \\ \therefore y=\frac{2x-24}{6} \\ \\ \therefore \boxed{y=\frac{1}{3}x-4}

This line has a slope m=\frac{1}{3} and cuts the y-axis at b=-4

By using graph tools, we get the graph shown below, then:

x=-6 \\ \\ y=-6 \\ \\ \\ Since \ u=y \ and \ v=x, then: \\ \\ u=-6 \\ \\ v=-6

8 0
3 years ago
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Answer:

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Step-by-step explanation:

We need to try this equation for all of the numbers in the table.

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Answer:

Step-by-step explanation:

4.

2ab cos C=a²+b²-c²

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cos C=-443/868

C=cos^{-1}(-443/868)≈120.688≈120.69°

5.

by sine formula

m∠B=180-(62+55)=180-117=63°

\frac{AC}{sin~B} =\frac{AB}{sin~C} \\\frac{240}{sin 63} =\frac{AB}{sin~55} \\AB=\frac{sin~55}{sin~63} \times 240 \approx 220.645 \approx 220.65 ~ft

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When rolling a number cube what is the probability of rolling a number greater than two
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Answer:

it is 5/6

Step-by-step explanation:

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