There are two <em>real</em> roots for the <em>quadratic</em> equation x² - 8 · x + 13 = 0, contained in the number x = 4 ± √2.
<h3>How to find the roots of a polynomial by completing the square</h3>
In this question we must apply algebraic handling to simplify a <em>quadratic</em> equation and find the roots that satisfy the expression. Completing the square consists in transforming part of the equation into a <em>perfect square</em> trinomial, and then we clear for x:
x² - 8 · x + 13 = 0
x² - 8 · x + 16 = 3
(x - 4)² = 3
x - 4 = ± √2
x = 4 ± √2
There are two <em>real</em> roots for the <em>quadratic</em> equation x² - 8 · x + 13 = 0, contained in the number x = 4 ± √2.
To learn more on quadratic equations: brainly.com/question/2263981
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35/7 (total $ divided by total units)= 5
1 unit = $5
Sitis units times 5
4 • 5 = $20
Sitis has $20
Answer:
Open a savings account
Step-by-step explanation:
Answer:
I think that it's 12 but I don't know for sure.
Step-by-step explanation:
Answer:
Ix - 950°C I ≤ 250°C
Step-by-step explanation:
We are told that the temperature may vary from 700 degrees Celsius to 1200 degrees Celsius.
And that this temperature is x.
This means that the minimum value of x is 700°C while maximum of x is 1200 °C
Let's find the average of the two temperature limits given:
x_avg = (700 + 1200)/2 =
x_avg = 1900/2
x_avg = 950 °C
Now let's find the distance between the average and either maximum or minimum.
d_avg = (1200 - 700)/2
d_avg = 500/2
d_avg = 250°C.
Now absolute value equation will be in the form of;
Ix - x_avgI ≤ d_avg
Thus;
Ix - 950°C I ≤ 250°C
