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3 years ago

13

20 points 2^-3 * 2^x * 2^x+2

1 answer:

Ivanshal [37]3 years ago

8 0

Apply a law of exponents. When multiplying you add the exponents:-

2^-3 * 2^x * 2^(x+2)

= 2 ^(-3 + x + x + 2)

= 2^(2x - 1) Answer

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PLEASE HELP! THANK YOU! :)

Furkat [3]

Answer:

BiG ChUnGuS moo

Step-by-step explanation:

6 0

2 years ago

Julie is a math tutor. She charges each student $210 for the first 7 hours of tutoring and $20 for each additional hour.

Maksim231197 [3]

She spent 17 hours tutoring

$210 = 7 hours

$20 x 10 hours = $200

$210 + $200 = $410
7 Hours + 10 Hours = 17 Hours

8 0

2 years ago

Read 2 more answers

How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy

lisov135 [29]

Answer:

$300\; \rm lb$ .

Step-by-step explanation:

Let $x$ represent the mass (in pounds) of that $15\%$ copper alloy required, such that the final mixture would contain $25.5\%$ copper by mass.

Consider: if $x$ pounds of that $15\%$ copper alloy is mixed with $700$ pounds that $30\%$ copper alloy, what would be the mass of copper in the mixture?

Mass of copper in $x$ pounds of that $15\%$ copper alloy: $(0.15\, x)\; \rm lb$ .
Mass of copper in $700$ pounds of that $30\%$ copper alloy: $700 \times 0.30 = 210\; \rm lb$ .

Therefore, the mixture would contain $(210 + 0.15\, x) \; \rm lb$ of copper.

The mass of that mixture would be $(700 + x)\; \rm lb$ . The mass fraction of copper in that mixture would be:

$\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%$ .

This ratio is supposed to be equal to $25.5\%$ . These two pieces of equations combine to give an equation about $x$ :

$\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%$ .

$\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255$ .

Simplify and solve for $x$ :

$210 + 0.15\, x= 0.255\, (700 + x)$ .

$(0.255 - 0.15)\, x= 210 - 0.255 \times 700$ .

$\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300$ .

Therefore, $300\; \rm lb$ of that $15\%$ alloy would be required.

4 0

2 years ago

200 kg of brass is melted down and cast into ornamental frogs, each weight 3/20kg. How many frogs are made?

Savatey [412]

Answer:

1,333 frogs

Step-by-step explanation:

okay so we know that mass remains conserved no matter where you are.

same here ^^

if the total mass of brass is 200 kg

the total mass of the new frogs formed from it when put together will be the same :)

and if there were n such frogs formed

we have,

total mass = n × mass of each frog

200 = n × 3/ 20

n = 4000/ 3

so it becomes something like 1,333.33

that is nearly 1,333 frogs can be made out of 200 kg of brass each weighing 3/ 20kg (the last ones a bit less to make upto 200kg)

5 0

2 years ago

-3x²+9x-6 find the terms, constant, Factors, and Coefficients.

Anastasy [175]

Answer:

WAIT A MINUTE MR. POSTMAN

Step-by-step explanation:

7 0

2 years ago