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leonid [27]
3 years ago
10

LAST TRY!!!! I HAVE THIS LAST QUESTION AND 4 MIMNTES LEFT!!!!!! PLS HELP OUT!!! WILL GIVE BRANLIEST!!! AT LEAST TAKE A LOOK!!! S

HARE YO SMARTNESS! ONLY IF YOUR 100% SURE!
Which angles would apply to the consecutive exterior angles theorem?

A) 1 and 7; 2 and 8
B) 1 and 8; 2 and 7
C) 1 and 5; 3 and 7
D) 2 and 6, 4 and 8

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
5 0

Answer:

Step-by-step explanation:

Consecutive exterior angles lie outside on the same side of a transversal.

So it should be 3,45 and 6

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F(x)=4x2-3x+5 f(2) find function value
Dovator [93]

Hello!

This question is an example of function notation. Function notation is basically f(x) , said as "f of x". To solve this problem, you need to substitute x = 2 into each x-value in this equation. F(2) is written as function notation, while x = 2 is not.

F(2) = 4x² - 3x + 5

F(2) = 4(2)² - 3(2) + 5

F(2) = 4(4) - 6 + 5

F(2) = 16 - 6 + 5

F(2) = 15

Therefore, the value of F(2) is 15.

8 0
3 years ago
1. A buoy floats 19 yards from the eastern most point of a boat and 15 yards from the western most point of a second boat. The a
Black_prince [1.1K]

The laws of cosines and law of sines can be used given that two sides

and an included angle, or two angles a side are known.

Response:

1. The other angles in the triangle formed by the buoy are approximately;

  • <u>31.1° and 40.9°</u>

2. Distance of the helicopter from the first island is approximately;

  • <u>14.5 miles</u>

<h3>How is the Law of Sines and Cosines used?</h3>

Given parameters are;

Distance of the buoy from the easternmost point of a boat = 19 yards

Distance of the buoy from the westernmost point of the other boat = 15 yards

Angle formed from the buoy to the two boats = 108°

Distance between the two boats, <em>d</em>, is given by the law of cosines, as follows;

d² = 19² + 15² - 2 × 19 × 15 × cos(108°) = 586 - 570·cos(108°)

d = √(586 - 570·cos(108°))

By the law of Sines, we have;

\dfrac{d}{sin(108^{\circ})} = \mathbf{\dfrac{15}{sin(Angle \ formed \ from \ the \ boat \ on \ the \ West, \ \theta_1)}}

Which gives;

sin(\theta_1) = \mathbf{ \dfrac{15 \times sin(108^{\circ})}{\sqrt{586 - 570 \cdot cos(108^{\circ})} }}

The o

\theta_1 = arcsin \left( \dfrac{15 \times sin(108^{\circ})}{\sqrt{586 - 570 \cdot cos(108^{\circ})} } \right) \approx   \mathbf{31.1^{\circ}}

The other angles formed in the triangle containing the buoy are;

  • θ₁ ≈ <u>31.1</u>
  • θ₂ ≈ 180° - 108° - 31.1° ≈<u> 40.9°</u>

2. Distance between the two islands = 20 miles

Angle of elevation with one island = 15°

Angle of elevation with the second island = 35°

Required:

The mileage (distance travelled) of the helicopter.

Solution:

Let <em>A</em> represent the island that has an angle of elevation to the helicopter

of 15°, and let <em>B</em> represent the other island.

Angle formed by the helicopter and the two island, θ, is found as follows;

θ = 180° - (15° + 35°) = 130°

By the Law of Sines, we have;

\dfrac{20}{sin(130^{\circ})} = \mathbf{ \dfrac{Distance \ from \  island \ A }{sin(35^{\circ})}}

Which gives;

Distance \ of \ helicopter \ from \  island \ A = \mathbf{ \dfrac{20}{sin(130^{\circ})} \times sin(35^{\circ})}

Mileage \ from \ island \ A =  \dfrac{20}{sin(130^{\circ})} \times sin(35^{\circ}) \times cos(15^{\circ}) \approx 14.5

  • The mileage of the helicopter from the first island is approximately <u>14.5 miles</u>

Learn more about the Law of Sines and Cosines here:

brainly.com/question/8242520

brainly.com/question/2491835

7 0
2 years ago
What are the two systems of equations for this graph?​
ANTONII [103]
The system of equations to this graph is (1,1)
7 0
3 years ago
Can i get help...plzzz
Digiron [165]

Answer:P ERRA

Step-by-step explanation:

JAJJAA

6 0
3 years ago
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5) What is the smallest number by which 1323 must be multiplied so that the product is a perfect
Westkost [7]

Answer:

the smallest number is 7

5 0
3 years ago
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