Question

Help on college algebra, question is on the picture!

Answer 1

$\frac{7x+1}{x-2} + \frac{2}{x} = \frac{-4}{ x^{2} -2x}$ is given 
here , $\frac{7x+1}{x-2} + \frac{2}{x} = \frac{-4}{ x^{2} -2x}$ 
or, $\frac{7x^{2} +x +2x-4 }{x(x-2)} = \frac{-4}{ x^{2} -2x}$
or,$\frac{7 x^{2} +3x-4}{ x^{2} -2x} = \frac{-4}{ x^{2} -2x}$
or,7x²+3x-4=-4
or,7x²+3x=0
or,x(7x+3)=0
Either,x=0| Or,7x+3=0
                |or,7x=-3
                |or,x=$\frac{-3}{7}$
So , the solution set is S={0,-$\frac{3}{7}$}