Question

6k²+16k=0 x²-5x= 0 ANSWer these noeww!

Answer 1

Answer:

1) k = (-8)/5

2) x = 5

Step-by-step explanation:

1)

$6 {k}^{2} + 16k = 0$

$= > 2k(3k + 8) = 0$

$= > 3k + 8 = \frac{0}{2k} = 0$

$= > 3k = - 8$

$= > k = \frac{ - 8}{3}$

2)

${x}^{2} - 5x = 0$

$= > x(x - 5) = 0$

$= > x - 5 = \frac{0}{x} = 0$

$= > x = 5$