Bread rolls = BR
Ketchup = K
Sausages = S
2BR +1K + 3S = £10 - 45p
2BR + 1K + 3S = £9.55
2BR = 1.40 x 2 = £2.80
1K = £1.80
£2.80 + £1.80 + 3S = £9.55
3S = £9.55 - £2.80 - £1.80
3S = £4.95
£4.95 / 3 = BR
S = £1.65
The answer is £1.65 for one pack of sausages
For this case we have the following equation:

We must find the value of "x":
We apply cube root on both sides of the equation to eliminate the exponent:
![x = \sqrt [3] {375}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B375%7D)
We can write 375 as 
So:
![x = \sqrt [3] {5 ^ 3 * 3}\\x = 5 \sqrt [3] {3}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B5%20%5E%203%20%2A%203%7D%5C%5Cx%20%3D%205%20%5Csqrt%20%5B3%5D%20%7B3%7D)
Then, the correct options are:
![x = \sqrt [3] {375}\\x = 5 \sqrt [3] {3}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B375%7D%5C%5Cx%20%3D%205%20%5Csqrt%20%5B3%5D%20%7B3%7D)
Answer:
Option A and B
Answer:
w=10
Step-by-step explanation:
You would have to set 5w-4=46.
5w-4=46
Add 4 to both sides
5w=50
Divide both sides by 5
w=10
The answer is C
call the length is a => the diagonal is a+1
11^2 + a^2=(a+1)^2
<=> 121 + a^2=a^2 + 2a +1
<=>120=2a
<=> a=60
An <em>algebraic expression</em> is one that consists of both <u>number(s)</u> and an <u>alphabet(s)</u>. The <em>required</em> answers are:
i. Distance from Chenoa's <u>house</u> to the <em>coffee shop</em> = 6.0 miles
ii. D<u>istance</u> from <em>coffee shop</em> to Chenoa's <u>school</u> = 1.5 miles
iii. <em>Distance</em> from Chenoa's <u>house</u> to her <u>school</u> = 7.5 miles
An <em>algebraic expression</em> is one that consists of both <u>number(s)</u> and an <u>alphabet(s)</u>. The <em>alphabet</em> is referred to as the <u>unknown</u> whose <u>value</u> has to be <em>determined</em>.
In the given question, let the <u>distance</u> from the <em>coffee shop</em> to Chenoa's <u>school</u> be represented by y.
So that;
The <u>distance</u> from Chenoa's house to the <em>coffee shop</em> = (2y + 3) miles.
The <em>total distance</em> from Chenoa's <u>house</u> to her <u>school </u>= 5y.
This implies that:
(2y + 3) + y = 5y
3y + 3 = 5y
3 = 5y - 3y
2y = 3
y = 
= 1.5
The <em>distance</em> from the <em>coffee shop</em> to Chenoa's <u>school</u> is 1.5 miles.
Thus;
(2y + 3) = ( 2(1.5) + 3)
= 6
The <u>distance</u> from Chenoa's <u>house</u> to the <em>coffee shop</em> is 6 miles.
And,
5y = 5(1.5)
= 7.5
The <em>total distance</em> from Chenoa's <u>house</u> to her <u>school</u> is 7.5 miles.
For more clarifications on algebraic expressions, visit: brainly.com/question/12792264
#SPJ1