Answer:
m∠CGF=25°
Step-by-step explanation:
we know that
In a circle, a radius that bisects a chord is perpendicular to the chord
so
CS is perpendicular to AC
The triangle GFC is a right triangle
Remember that the sum of the measures of the interior angles in a triangle must be equal to 180 degrees
m∠CGF+m∠GFC+m∠GCF=180°
we have
m∠GFC=90°
m∠GCF=65°
substitute
m∠CGF+90°+65°=180°
m∠CGF+155°=180°
m∠CGF=180°-155°
m∠CGF=25°
Y=mx+b now just re do them
We need more information. what graph?
So, since they are similar, so 9:12 and 15:x
to get to 12, you have to multiply 9 by 4/3. so multiply 15 by 4/3 to get your answer, which is 20.
Answer:
Distance around the track = 194.3 metres.
Step-by-step explanation:
Given: The two straight sides are of the track are 50 metres each
Diameter of each bend = 30 metres
Thus;
radius of the bends =
=
= 15 metres
So that,
length of the semicircular bend = x 2r
= r = x 15
= 47.143
length of each semicircular bend is 47.14 metres.
Distance around the track = addition of the length of each straight sides + addition of the length of the bends
= 50 + 50 + 47.14 + 47.14
= 194.28
Therefore,
Distance around the track = 194.3 metres.