Let V, be the rate in still water and let C = rate river current
If the boat is going :
upstream, its rate is V-C and if going
downstream, its rate is V+C,
But V = 5C, then
Upstream Rate: 5C - C = 4 C
Downstream rate: 5C+C = 6C
Time = distance/Rate, (or time = distance/speed) , then:
Upstream time 12/4C and
Downstream time: 12/.6C
Upstream time +downstream time:= 2h30 ' then:
12/4C + 12/.6C = 2.5 hours
3/C + 2/C = 5/2 (2.5 h = 5/2)
Reduce to same denominator :
5C = 10 and Rate of the current = 2 mi/h
Answer: I think It's D
Step-by-step explanation: Comment if im right or wrong please
Answer:
12.5lb
Step-by-step explanation:
5lbs+6lb=11lb
11oz+12oz=1.5lbs
11lb+1.5lb=12.5
Triple t ⇒ 3t
add the result to u ⇒ 3t + u
multiply what you have by v ⇒ (3t + u)v
Since it is instructed not to simplify, we perform the distributive property of multiplication.
(3t + u)v = 3tv + uv
Answer:
y=-5/4x-8
Step-by-step explanation:
2=-5/4(-8)+b
2=10+b
2-10=10-10b
-8=b