Ask question

Ask question

All categories

Ilia_Sergeevich [38]

3 years ago

6

The length of a rectangle is 3 times the width. The difference between the length and the width is 8 feet. Determine the rectang

le’s width?

1 answer:

Fynjy0 [20]3 years ago

5 0

Answer:

Width = 4 feet

Step-by-step explanation:

Let l = length

Let w = width

l = 3w

l - w = 8

3w - w = 8

2w = 8

w = 4

You might be interested in

A soccer player uses her head to hit a ball up in the air from a height of 2 meters with an initial vertical velocity of 5 meter

ozzi

Answer:

The ball will hit the ground in 1.33 s if no one touches it. The equation has 2 real solutions.

Step-by-step explanation:

The ball will hit the ground when its height is equal to 0 meters, therefore using this value in the expression and solving for "t" will give us the correct solutions.

$h = -4.9*t^2 + 5*t + 2\\\\-4.9*t^2 + 5*t + 2 = 0\\\\t_{1,2} = \frac{-5 \pm \sqrt{5^2 - 4*(-4.9)*(2)}}{2*(-4.9)}\\\\t_{1,2} = \frac{-5 \pm \sqrt{64.2}}{-9.8}\\\\t_{1,2} =\frac{-5 \pm 8.0125}{-9.8}\\\\t_1 = \frac{-5 - 8.0125}{-9.8} = 1.33 \text{ s}\\\\t_2 = \frac{-5 + 8.0125}{-9.8} = -0.3 \text{ s}$

The ball will hit the ground in 1.33 s if no one touches it. The equation has 2 real solutions.

8 0

3 years ago

a die rolled. the set of equally likely outcomes is 1 ,2, 3, 4, 5, 6. find the probability of getting a 10.

Sidana [21]

Answer:

1 in 12

Step-by-step explanation:

hard to explain

5 0

3 years ago

A jewelry maker purchased 20 inches of gold chain.She used 3/8 of the chain for a bracelet. How many inches of gold did she have

Mazyrski [523]

Answer:

12.5 inches of gold chain.

Step-by-step explanation:

To get the remaining chain of gold we need to calculate

8/8 - 3/8 = 5/8 of 20 inches

then multiply:

20 * 5/8 = 100/8

100/8 = 12.5 inches

7 0

3 years ago

. Exam scores for a large introductory statistics class follow an approximate normal distribution with an average score of 56 an

Andru [333]

Answer:

0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 56, \sigma = 5, n = 20, s = \frac{5}{\sqrt{20}} = 1.12$

What is the probability that the average score of a random sample of 20 students exceeds 59.5?

This is 1 subtracted by the pvalue of Z when $X = 59.5$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{59.5 - 56}{1.12}$

$Z = 3.1$

$Z = 3.1$ has a pvalue of 0.9990.

So there is a 1-0.9990 = 0.001 = 0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

3 0

3 years ago

The pieces of a puzzle are placed half by Giulio, one fifth by Marco and Fabrizio in equal parts, while Michele arranges on the

denis23 [38]

Answer:

Not exactly sure but I think it should be 30 pieces

Step-by-step explanation:

3 0

2 years ago