Answer:
a. -5
b.-5
c.-5
Step-by-step explanation:
In order to find the average rate of change of a function , we divide the change in the output value by the change in the input value.
Generally, the average rate of change (ARC) on an ecuatios between two points (x1,f(x1)) and (x2,f(x2)) is
- ARC = [f(x2)-f(x1)]/ (x2-x1)
<em>In case a)</em>
f(-1)= -5*(-1)-8=5-8= -3 f(3)= -5*3-8= -23
Then ARC= (-23-(-3))/(3-(-1))=-20/4=-5
<em>In case b)</em>
f(a)= (-5a-8)
f(b)= (-5b-8)
Then ARC= [(-5b-8)-(-5a-8)]/(b-a)= (-5b+5a)/(b-a)= -5(b-a)/(b-a)= -5
<em>In case c)</em>
f(x)= -5x-8
f(x+h)= -5(x+h)-8= -5x-5h-8
then ARC= [(-5x-5h-8)-(-5x-8)]/(x+h-x) =-5h/h= -5
You do --12/15---you see that this can be simplified by the same factor 3-- si you divide by 3 on both numbers thus you get---4/5 as the answer
Answer:
625 ft^2
Step-by-step explanation:
Given
--- perimeter
Required
The largest area
The perimeter is calculated as:

So, we have:

Divide both sides by 2

Make L the subject

The area is calculated as:

Substitute 

Open bracket

Differentiate with respect to W

Set to 0; to get the maximum value of W

Collect like terms

Divide by -2

So, the maximum area is:




Answer:
5.5
Step-by-step explanation:
8.25/3=2.75
2.75 times 2 is 5.5
<h3>The ladder will reach a height of 11.8 feet up the wall</h3>
<em><u>Solution:</u></em>
The ladder, wall and base of the ladder from wall forms a right angled triangle
Length of ladder forms the hypotenuse
Length of ladder = 12 foot
base of the ladder from wall = 2 feet
<em><u>To find: height of wall</u></em>
By pythagoras theorem.

Where,
"c" is the Length of ladder
"a" is the base of the ladder from wall
"b" is the height of wall
Substituting the values,

Thus, the ladder will reach a height of 11.8 feet on wall