Simplify numbers to layman terms.
will be a little more than
, since
is 3.14.
will be a little less than -4, since
.
will be a little more than 4, since ![\sqrt{18}>\sqrt{16}](https://tex.z-dn.net/?f=%5Csqrt%7B18%7D%3E%5Csqrt%7B16%7D)
will be a little less than -2, since ![-\sqrt{7}](https://tex.z-dn.net/?f=-%5Csqrt%7B7%7D%3C-%5Csqrt%7B4%7D)
Now we can order them.
![-\sqrt{18},-\sqrt{7},\frac{\pi}{2},\sqrt{18}](https://tex.z-dn.net/?f=-%5Csqrt%7B18%7D%2C-%5Csqrt%7B7%7D%2C%5Cfrac%7B%5Cpi%7D%7B2%7D%2C%5Csqrt%7B18%7D)
Hope this helps.
頑張って!
Answer:
5
Step-by-step explanation:
7x plus 15 is 50
7x=35
can i pls have brainliest
Answer:
There are three fourths in 3 fourths
Step-by-step explanation:
Fourth represents ![\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D)
Therefore, 3 fourths will be given as:
![3\times (\frac{1}{4}) = \frac{3}{4}](https://tex.z-dn.net/?f=3%5Ctimes%20%28%5Cfrac%7B1%7D%7B4%7D%29%20%3D%20%5Cfrac%7B3%7D%7B4%7D)
Therefore,
No. of fourths in 3 fourths = ![\frac{\frac{3}{4}}{\frac{1}{4}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B3%7D%7B4%7D%7D%7B%5Cfrac%7B1%7D%7B4%7D%7D)
No. of fourths in 3 fourths = ![\frac{3}{4}\times \frac{4}{1} = 3](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%5Ctimes%20%5Cfrac%7B4%7D%7B1%7D%20%3D%203)
9514 1404 393
Answer:
Step-by-step explanation:
The perimeter is the sum of the side lengths. Those that are unmarked are assumed to match the length of the nearest parallel side.
Clockwise from upper left, the perimeter is ...
P = 8 + 5 + 4 + 4.5 + 15 + 5.6 + 4 + 5
P = 51.5 . . . feet
__
The area can be figured using the formulas for area of a parallelogram, rectangle, and trapezoid. These are, respectively, ...
- A = bh
- A = bh
- A = (1/2)(b1 +b2)h
parallelogram area = (8 ft)(3 ft) = 24 ft²
rectangle area = (8 ft)(4 f) = 32 ft²
trapezoid area = (1/2)(8 ft +15 ft)(4 ft) = 46 ft²
Then the total area of the figure is ...
A = 24 ft² +32 ft² +46 ft²
A = 102 ft²
_____
<em>Additional comment</em>
The figure shown is impossible. The trapezoid side lengths and height are consistent with a bottom base of length 14, not 15.