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densk [106]
4 years ago
7

You exercised 24 hours each month for a year. How many hours did you exercise by the end of the year? You may be able to do the

math mentally thanks to expanded notation and the Distributive Property.
Mathematics
2 answers:
dedylja [7]4 years ago
7 0

Answer:

288 hours.

Step-by-step explanation:

You exercise 24 hours in 1 month.

There are 12 months in one year.

24 * 12 = 288

Therefore, you exercised 288 hours in one year.

alexgriva [62]4 years ago
4 0

Answer:

Calculation with Distribution

24 (1+1+1+1+1+1+1+1+1+1+1+1)

24*1+24*1+24*1+24*1+24*1+24*1+24*1+24*1+24*1+24*1+24*1+24*1

24+24+24+24+24+24+24+24+24+24+24+24

288 hours

You did 288 hours of exercise.

Calculation without Distribution

24(1+1+1+1+1+1+1+1+1+1+1+1)

24(12)

288 hours

You did 288 hours of exercise.

Step-by-step explanation:

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Ángel A And B are suplementary. Ángle A has a measure of 80.ehat is the measure of B?
zavuch27 [327]
Because supplementary angles means mA + mB = 180.
Then subtract 80 from 180 which will get you 100.
So B = 100
7 0
4 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
20. The H.M. between 2 and 8 is<br>(1 marks )​
e-lub [12.9K]

Answer as an improper fraction = 16/5

Answer as a mixed number = 3 & 1/5

Answer in decimal form = 3.2

All of those values represent the same thing, but written in a different way.

=============================================================

Explanation:

I'm assuming HM stands for Harmonic Mean in this case.

If so, then we apply the reciprocal operation to each value to get 1/2 and 1/8 (from 2 and 8 respectively).

Add up those fractions:

1/2 + 1/8 = 4/8 + 1/8 = 5/8

Now we'll divide n = 2 over that result. The n = 2 refers to the number of items in the original set.

n divide over (5/8) = 2*(8/5) = 16/5 which is the answer as an improper fraction

-----------

To convert to a mixed number, we can do the following:

16/5 = (15+1)/5

16/5 = 15/5 + 1/5

16/5 = 3 + 1/5

16/5 = 3 & 1/5

Or if you need the answer in decimal form, then using a calculator would get you 16/5 = 3.2

6 0
3 years ago
Help please I need it please please help me in it
Snezhnost [94]

Answer:

115.08

Step-by-step explanation:

6 0
3 years ago
BRANILIEST ANSWER GETS ALOT OF POINTS I NEED HELP PLZZ
yulyashka [42]
For this problem, I'd use cross-multiplication.

9/12 = x/8.

When cross multiplying, multiply 12*x and 9*8. This leads to a new equation:

12x = 72.

Then you solve as an algebra problem.

*Divide 12 on both sides*

x = 6.
6 0
4 years ago
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