Answer:
The correct answer is c. 3/16.
Explanation:
In the given question two traits being studied, the traits are flower color and seed shape.
This is a typical Mendel’s dihybrid cross. According to the question purple colour (P) and round seed (R) are dominant traits.
When heterozygous purple-flowered (Pp), round-seeded (Rr) individuals are crossed, four different types of plants are produced phenotypically in the ratio 9:3:3:1.Out of 16 offspring, 9 are purple flowered, round seeded pea plants, 3 pea plants are white-flower with round seed, 3 are purple- flower with wrinkled seed and 1 pea plant is white-flowered with wrinkled seed pea plant is produced.
Here is your answer
No
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REASON:
Amoeba reproduces by the process of binary fusion which is an asexual mode of reproduction.
Since, in asexual method mitosis cell division takes place, same DNA material is transferred to the offsprings so no new traits and genes can be found in offsprings.
However in some case due to genetic drift or mutation, slight variations can be found in progeny.
But this is very exceptional.
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