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nirvana33 [79]
3 years ago
11

Please help me answer these!!! Thanks :)

Mathematics
1 answer:
Andrei [34K]3 years ago
6 0
-2-(+7) is the same thing at -2-7 which is -9

-3 \frac{2}{7} -(- \frac{5}{7} ) is the same thing as (-3 \frac{2}{7}) + (\frac{5}{7}) which is - \frac{18}{7} or -2 \frac{4}{7}

Last but not least the last one is the Associative Property based on definition listed below :)
Associative Property:<span> When three or more numbers are added, the sum is the same regardless of the grouping of the addends. For example (2 + 3) + 4 = 2 + (3 + 4)</span>
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Solve each equation.<br> 11. A number x divided by nine is two.
ivanzaharov [21]

Answer:

18 is the correct answer to this

Step-by-step explanation:

18/9=2

6 0
3 years ago
Plz help i need this asap
Assoli18 [71]

Answer:

option B

Step-by-step explanation:

7 0
3 years ago
Solve {2x — y = 13; 3x + y = 12
Morgarella [4.7K]

Answer:

{x,y}={5,-3}

Step-by-step explanation:

8 0
2 years ago
Let f(x)=-2x+4 and g(x)=-6x-7. find f(x)-g(x)<br><br>Please can someone help me?
Travka [436]
F(x)-g(x)
=(-2x)+4-(-6x-7)
=(-2x)+4-(-6x)+7
=(-2x)+4+6x+7
=4x+11
4 0
3 years ago
Write an equation in general form for the line passing through (-12,-1) and perpendicular to the line whose equation is 6x-y-4=0
Rus_ich [418]

The Solution:

Given the equation of a line:

6x-y-4=0

We are required to find the equation of a line that is perpendicular to the given line and passes through the point (-12,-1).

Step 1:

Determine the slope of 6x-y-4=0.

\begin{gathered} \text{  Express y in terms of x.} \\ 6x-4=y \\ y=6x-4 \end{gathered}

The coefficient x, after making y the subject of the formula, is the slope of the given line. That is:

\begin{gathered} \text{ The slope of }6x-y-4=0\text{ is 6} \\  \\ Slope=m_1=6 \end{gathered}

Step 2:

Find the slope of the required line:

Since the two lines are perpendicular, the slope is:

\begin{gathered} m_2=\frac{-1}{m_1}=\frac{-1}{6} \\  \end{gathered}

Step 3:

Find the equation of the line that passes through point (-12,-1)

By formula,

y-y_1=m_2(x-x_1)

In this case,

\begin{gathered} x_1=-12 \\ y_1=-1 \end{gathered}

Substituting these values in the formula, we get the required equation is:

\begin{gathered} y--1=\frac{-1}{6}(x--12) \\  \\ y+1=-\frac{1}{6}(x+12) \end{gathered}

Cross multiplying, we get

\begin{gathered} 6y+6=-x-12 \\  \\ 6y+x+6+12=0 \\  \\ 6y+x+18=0 \end{gathered}

Therefore, the correct answer is:

6y+x+18=0

5 0
1 year ago
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