Come on now, Tayala !
What if I say to you:
"Start with 3 cows, take away 7 cows, and then add 14 cows. How many are there ?"
Don't let the little 't' scare you. It doesn't matter one bit what 't' really is. It can be
a number, a teacher, a tiger, or a teacup. Whatever it is, you start with 3 of them,
take away 7 of them, and then add on 14 of them. How many are there ?
Hint: If there are not ten of them, then go back and look at the cows again.
1) No; you are incorrect. "0" is NOT a solution.
Plug in "0" for "x" ;
8*0² + 23 =? 823? ;
8*0 + 23 =? 823? ;
0 + 23 = ? 823 ? ; No! ; "0 + 23 = 23 " ; NOT "823" .
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2) The answers: x = 10, -10 ; or, write as: x = ± 10 .
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To solve:
GIven: 8x² + 23 = 823 ;
Subtract "23" from EACH SIDE of the equation:
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8x² + 23 - 23 = 823 - 23 ;
to get:
8x² = 800 ;
Now, divide EACH SIDE of the equation by "8" ;
8x² / 8 = 800 / 8 ;
to get: x² = 100 ;
Take the "square root" of EACH SIDE of the equation; to isolate "x" on one side of the equation; and to solve for "x" ;
√(x²) = √(100) ;
x = <span>± 10 .
The answers: x = 10, -10 ; or, write as: x = </span><span>± 10 .
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Answer: B and D
Step-by-step explanation:
Answer:
-213.98
Step-by-step explanation:
Answer:
it’s the third one
Step-by-step explanation:negatives are never higher than numbers without negatives