![5\cdot(\frac{1}{5^3})\ne5\cdot(5^3)](https://tex.z-dn.net/?f=5%5Ccdot%28%5Cfrac%7B1%7D%7B5%5E3%7D%29%5Cne5%5Ccdot%285%5E3%29)
His answer is not correct, when we have a power on the denominator it is dividing and not multiplying, in this case while the expression on the left is being divided the other one is multiplying.
also you could rewrite the expressions like so remembering that powers that are on the denominator can be written as negative powers.
Answer:
hi
Step-by-step explanation:
hi
First, we should answer two simple questions.
1. How many ways can we travel from a-b?
2. How many ways can we travel from b-c?
This is given in the problem - because there are 7 roads connecting a to b, there are 7 ways to get from a-b. Because there are 6 roads from b-c, there are 6 ways to get from b-c.
Now that we understand this, we can use some logic to figure out the rest of the problem. Let's think about each case.
Let's go from a-b. We'll choose road 1 of 7. Now that we are in b, we have 6 more choices. This means that there are 6 ways to get to from a-c if we take road 1 when we go to b.
If we take any road going from a-b, there will be 6 options to get from b-c.
So, we can just add up the number of options because we know that there are 6 routes per road from a-b. This is simply 7*6 = 42. So, there are 42 ways to travel from a to c via b.
Answer:
Step-by-step explanation:
Wee
The first differences are 8, 14, 20.
The second differences are 6.
Half of 6 is 3, so the first term of the sequence is 3n^2.
If you subtract 3n^2 from the sequence you get 0,-1,-2,-3 which has the nth term of -n + 1.
Therefore your final answer will be 3n^2 - n + 1