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ozzi
3 years ago
5

How many sides do a square have

Mathematics
2 answers:
Whitepunk [10]3 years ago
8 0
Square = quadrilateral = all quadrilaterals have 4 sides
loris [4]3 years ago
4 0
A square has four sides. Hope this helps you.
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Use an area model to show the product of 8x2.23 write your answer in standard form answer
mixas84 [53]

Answer:

17.84

Step-by-step explanation:

2.23

    8 x

-----------

17.84

4 0
2 years ago
Read 2 more answers
If g(x) is a linear function such that g(-3) = 2 and g(1) = -4, find g(7).
eimsori [14]
<h3>Answer:   -13</h3>

=======================================

Explanation:

g(-3) = 2 means x = -3 and y = 2 pair up together to form the point (-3,2)

g(1) = -4 means we have the point (1,-4)

Find the slope of the line through the two points (-3,2) and (1,-4)

m = (y2-y1)/(x2-x1)

m = (-4-2)/(1-(-3))

m = (-4-2)/(1+3)

m = -6/4

m = -3/2

m = -1.5

The general slope intercept form y = mx+b turns into y = -1.5x+b after replacing m with -1.5

Plug in (x,y) = (-3,2) which is one of the points mentioned earlier and we end up with this new equation:  2 = -1.5*(-3) + b

Let's solve for b

2 = -1.5*(-3)+b

2 = 4.5 + b

2-4.5 = 4.5+b-4.5 .... subtract 4.5 from both sides

-2.5 = b

b = -2.5

Therefore, y = mx+b becomes y = -1.5x-2.5 meaning the g(x) function is g(x) = -1.5x-2.5

The last step is to plug in x = 7 and compute

g(x) = -1.5*x - 2.5

g(7) = -1.5*7 - 2.5

g(7) = -10.5 - 2.5

g(7) = -13

6 0
3 years ago
Read 2 more answers
How many solutions does the system 2y=10x-14 and 5x-y=7 have? need worked out step by step please!
VLD [36.1K]
2y=10x-14
5x-y=7

Divide both sides by 2 in the 1st equation
y=5x-7
Now substitute is to 2nd equation 
5x-5x+7=7
0=0

Therefore there is no solution or it is inconsistent 
3 0
3 years ago
Read 2 more answers
7. Please solve by substitution:<br><br>y = 3x + 17<br>y = 2x + 23​
CaHeK987 [17]
3x+17=2x+23

5x=40

40/5=8

x=8
7 0
3 years ago
Please help me<br><br> What is 8/1 ​ ÷ 4/3
creativ13 [48]

Answer:

6

Step-by-step explanation:

To check my work I used desmos

5 0
3 years ago
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