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Illusion [34]
3 years ago
10

could someone help me with this question:A bag contains sweets of three different colours: orange, blue and yellow. 2/5 of the s

weets are orange. there are 15 more blue sweets than yellow sweets.(a) how many blue sweets are there in the bag?(b) calculate the total number of sweets in the bag?​
Mathematics
1 answer:
marshall27 [118]3 years ago
5 0

Answer:

Yellow = x sweets

Blue = x + 15 sweets

Total number of sweets =\dfrac{10x+75}{3}

Step-by-step explanation:

A bag contains sweets of three different colours: orange, blue and yellow. It is given that

  • \frac{2}{5} of the sweets are orange, then \frac{3}{5} of the sweets are blue and yellow;
  • there are 15 more blue sweets than yellow sweets.

Let x be the number of yellow sweets, then x + 15 is the number of blue sweets.

In total, there are x + x + 15 = 2x + 15 blue and yellow sweets.This number of sweets is exactly \frac{3}{5} of all sweets, so there are

\dfrac{5(2x+15)}{3}=\dfrac{10x+75}{3} sweets in total.

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