Question

could someone help me with this question:A bag contains sweets of three different colours: orange, blue and yellow. 2/5 of the sweets are orange. there are 15 more blue sweets than yellow sweets.(a) how many blue sweets are there in the bag?(b) calculate the total number of sweets in the bag?​

Answer 1

Answer:

Yellow = x sweets

Blue = x + 15 sweets

Total number of sweets $=\dfrac{10x+75}{3}$

Step-by-step explanation:

A bag contains sweets of three different colours: orange, blue and yellow. It is given that

• $\frac{2}{5}$ of the sweets are orange, then $\frac{3}{5}$ of the sweets are blue and yellow;
• there are 15 more blue sweets than yellow sweets.

Let x be the number of yellow sweets, then x + 15 is the number of blue sweets.

In total, there are x + x + 15 = 2x + 15 blue and yellow sweets.This number of sweets is exactly $\frac{3}{5}$ of all sweets, so there are

$\dfrac{5(2x+15)}{3}=\dfrac{10x+75}{3}$ sweets in total.