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2 years ago

6

Hooke’s Law of Elasticity states that the force applied, y, varies directly with the distance a spring stretches, x (assuming th

e spring is not stretched past its elastic limit). If a force of 160 newtons stretches a spring 800 cm, how far will a force of 368 newtons stretch the same spring? Justify your answer.
Group of answer choices

F. It will stretch the same spring 73.6 cm because the equation is y equals 5x.

G. It will stretch the same spring 73.6 cm because the equation is y equals one fifth x..

H. It will stretch the same spring 1,840 cm because the equation is y equals 5x.

J. It will stretch the same spring 1,840 cm because the equation is y equals one fifth x..

1 answer:

Verdich [7]2 years ago

7 0

Answer:

H: It will stretch the same spring 1,840 cm because the equation is y equals 5x.

Step-by-step explanation:

800=y

160and368=x

You find the answer by dividing,

<h3>⁸⁰⁰⁄₁₆₀= ʸ⁄₃₆₈</h3>

800 divided by 160 equals 5 which means the equation is y equals 5x

and 368x5=1,840

also, do you go to college park?

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I need help with questions #7 and #8 plz

katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

$c^2 = a^2 + b^2 - 2ab \cos C$

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

7.

We use the law of cosines to find C.

$18^2 = 12^2 + 16^2 - 2(12)(16) \cos C$

$324 = 144 + 256 - 384 \cos C$

$-384 \cos C = -76$

$\cos C = 0.2$

$C = \cos^{-1} 0.2$

$C = 78.6^\circ$

Now we use the law of sines to find angle A.

Law of Sines

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

We know c and C. We can solve for a.

$\dfrac{a}{\sin A} = \dfrac{c}{\sin C}$

$\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}$

Cross multiply.

$18 \sin A = 12 \sin 78.6^\circ$

$\sin A = \dfrac{12 \sin 78.6^\circ}{18}$

$\sin A = 0.6535$

$A = \sin^{-1} 0.6535$

$A = 40.8^\circ$

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

8.

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

$a^2 = b^2 + c^2 - 2bc \cos A$

$b^2 = a^2 + c^2 - 2ac \cos B$

$c^2 = a^2 + b^2 - 2ab \cos C$

Find angle A:

$a^2 = b^2 + c^2 - 2bc \cos A$

$8^2 = 18^2 + 12^2 - 2(18)(12) \cos A$

$64 = 468 - 432 \cos A$

$\cos A = 0.9352$

$A = 20.7^\circ$

Find angle B:

$b^2 = a^2 + c^2 - 2ac \cos B$

$18^2 = 8^2 + 12^2 - 2(8)(12) \cos B$

$324 = 208 - 192 \cos A$

$\cos B = -0.6042$

$B = 127.2^\circ$

Find angle C:

$c^2 = a^2 + b^2 - 2ab \cos C$

$12^2 = 8^2 + 18^2 - 2(8)(18) \cos B$

$144 = 388 - 288 \cos A$

$\cos C = 0.8472$

$C = 32.1^\circ$

8 0

3 years ago

What is the complex conjugate of -8+12i

Nuetrik [128]

The complex conjugate of a + bi is a - bi

So, the complex conjugate of -8 + 12i is -8 - 12i.

5 0

3 years ago

Varvara68 [4.7K]

Answer:

Angela, a proportion is two equal ratios, kinda like 3/4 = 6/8.

If we call the number of cars c, then our proportion is 3/10 = c/100.

Cross multiplying, we get 10c = 300.

Dividing both sides by 10, c = 30.

3 0

3 years ago

Read 2 more answers

When you use word processor functions such as spell check and thesaurus to write a second draft you are

nirvana33 [79]

C. Revising because it should be your last stage in the writing process before you publish

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2 years ago

Read 2 more answers

Last year, Susan had 10,000 to invest. She invested some of it in an account that paid 6%

katrin2010 [14]

Answer:

In the account that paid 6% Susan invest $\$6,000$

In the account that paid 5% Susan invest $\$4,000$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

Part a) account that paid 6% simple interest per year

in this problem we have

$t=1\ years\\ P=\$x\\r=0.06$

substitute in the formula above

$I1=x(0.06*1)$

$I1=0.06x$

Part b) account that paid 5% simple interest per year

in this problem we have

$t=1\ years\\ P=\$10,000-\$x\\r=0.05$

substitute in the formula above

$I2=(10,000-x)(0.05*1)$

$I2=500-0.05x$

we know that

$I1+I2=\$560$

substitute and solve for x

$0.06x+500-0.05x=560$

$0.01x=560-500$

$0.01x=60$

$x=\$6.000$

therefore

In the account that paid 6% Susan invest $\$6,000$

In the account that paid 5% Susan invest $\$4,000$

6 0

3 years ago