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Anika [276]
3 years ago
5

Which best describes the three-dimensional figure obtained from rotating the figure around the y-axis?

Mathematics
1 answer:
svetoff [14.1K]3 years ago
8 0

Yo sup??

This question can be solved by just imagining the object formed or practically trying it out.

Therefore the correct answer to this question is option 2 ie

a cylinder with a radius of 1 unit.

Hope this helps.

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How to round 0.125 to the nearest whole
Gwar [14]
In the number 0.125, there is:
0 in the ones place,
1 in the tenths place,
2 in the hundredths place, and
5 in the thousandths place.

We want to round to the hundredths place, which is 2.
To do this we must look to the next digit.
If it's less than 5, we round down.
If it's more than 5, we round up.

The next digit is 5, though! So what do we do then?
Well, we would look to the next digit again<span> and decide from that.</span>
There isn't really a next digit to decide from, though, is there?

<span>In that case, we just round up.

and we get  0.13</span>
8 0
3 years ago
21/7 unit rate and equation
Vinil7 [7]
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4 years ago
Is the proportion A, B, D, or D?
Oksanka [162]

Answer:

C.)

Step-by-step explanation:

4/20=8/x

3 0
4 years ago
Using the discriminant, determine the number of real solutions.
uranmaximum [27]

Answer:

  C.  two real solutions

Step-by-step explanation:

Your quadratic matches the form ...

  ax^2 +bx +c = 0

for the values a=2, b=7, c=-15.

The discriminant is ...

  d = b^2 -4ac

For your values of a, b, c, the discriminant value is ...

  d = 7^2 -4(2)(-15) = 169

The discriminant is positive, indicating there are two real solutions.

_____

When the discriminant is negative, there are no real solutions, only complex solutions.

When the discriminant is zero, there is one real solution.

__

This equation factors as (2x-3)(x+5) = 0 and has solutions x=3/2, x=-5.

6 0
3 years ago
The equation 3x² - 4x + 6 = 0 has the roots α and β . Find the new equation with the roots (α/β²) and (β/α²) .
vova2212 [387]

Answer:

{ \tt{sum =  \alpha  +  \beta  =  \frac{4}{3} }} \\ { \tt{product =  \alpha  \beta  =  \frac{6}{3}  = 2}} \\  \\ new \: roots :  \\ { \bf{sum =  \frac{ \alpha }{ { \beta }^{2} }  +  \frac{ \beta }{ { \alpha }^{2} } }} \\  \\  { \bf{ =  \frac{ { \beta }^{2}  \alpha  +  { \alpha }^{2}  \beta }{ { (\alpha  \beta )}^{2} } }} \\  \\  = { \bf{   \frac{ \alpha  \beta ( \alpha  +  \beta )}{ {( \alpha  \beta )}^{2} } }} \\   \\ = { \tt{ \frac{2( \frac{4}{3}) }{2 {}^{2} } }} \\  \\ sum =  \frac{2}{3}  \\  \\ { \bf{product =  \frac{1}{ \alpha  \beta }}} \\  =  \frac{1}{2}  \\  \\ { \boxed{ \tt{equation : {2x}^{2}  +  \frac{4}{3} x +  1  }}}

7 0
3 years ago
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