Question

A medical team sent surveys to randomly selected households to determine the various health problems. The result of the survey is shown below.
health problems, number of patients

obesity 32

diabetes 54

heart problems 78

eye problems 112

dental problems 96


Note: The survey result for each health problem is mutually exclusive.


Based on the survey, what is the probability that a person chosen at random is a diabetic patient or an eye patient?

(SHOW WORK)

Answer 1

Answer:

Step-by-step explanation: First of all, we asume that each household recive a survey to check all health problems. After that we can sume all patients that means 32+54+78+112+96=372.

Now with a simple rule of three:

$\frac{112*100%}{372}$=30.11%. We have the 30.11% of the patients have eye problems.

$\frac{54*100%}{372}$=14.52%. We have the 14.52% of the patients have diabetes problems.

Answer 2

Answer: Our required probability would be $\dfrac{83}{186}$

Step-by-step explanation:

Since we have given that

Health problems    Number of patients

Obesity                              32

Diabetes                            54

Heart problems                 78

Eye problems                    112

Dental problems                96

Total                                  372

We need to find the probability that a person chosen at random is a diabetic patient or an eye patient.

So, P(diabetic patient) + P(eye patient)

$\dfrac{54}{372}+\dfrac{112}{372}\\\\=\dfrac{54+112}{372}\\\\=\dfrac{166}{372}\\\\=\dfrac{83}{186}$

Hence, our required probability would be $\dfrac{83}{186}$