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marishachu [46]
3 years ago
9

Adrianna, Deon, and Yoko jogged at Eisenhower Park today. Adrianna jogs at the park every 3

Mathematics
1 answer:
Dominik [7]3 years ago
3 0

Answer:the answer is 30

Step-by-step explanation hope this helped ☺️

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How to solve this <br><br> 4x-3(x-2)=21
Natasha_Volkova [10]

We can start by getting rid of parenthesis:

4x-3x+6=21

Then we can combine like terms:

x=21-6

x=15

So our end product is x=15.

Hope I helped soz if I'm wrong ouo.

~Potato.

Copyright Potato 2019.

4 0
4 years ago
Students in the science lab are measuring the mass of an object on a triple beam balance. The object has a mass of 38 grams. Com
const2013 [10]

Answer:

Step-by-step explanation:

5 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!
Naddik [55]

Answer:

Step-by-step explanation:

a) To find the length of diagonal XT, we can use the distance formula to get \sqrt{(-3-5)^{2}+(4-(-2))^{2}}=10

Since this is a rectangle, XT=YW, meaning YW=10 as well.

b) The area of a rectangle is given by length times width. The length is |-3-5|=8, and the width is |-2-4|=6. So the area is (8)(6)=48.

c) The perimeter is just 2(8+6)=28.

8 0
2 years ago
In 2000, the population of Big Springs was 13 thousand. Use the given doubling
trasher [3.6K]

Answer:

The answer is "26179.4".

Step-by-step explanation:

Assume year 2000 as t, that is  t =0.

Formula:

A= A_0e^{rt}

Where,

A_0 = \ initial \ pop \\\\r= \ rate \ in \ decimal \\\\t= \ time \ in \ year

for doubling time,

r = \frac{log (2)}{t} \\

r = \frac{\log (2)}{ 40} \\\\r= \frac{0.301}{40}\\\\r= 0.007

Given value:

A = A_0e^{rt} \\\\

A_0 = 13000

t= 40 \ years

when year is 2000, t=0 so, year is 2100 year as t = 100.

A = 13000 \times e^{et}\\\\A = 13000 \times e^{e \times t}\\\\A = 13000 \times e^{0.007 \times 100}\\\\A = 13000 \times e^{0.7}\\\\A= 13000\times 2.0138\\\\A = 26179.4

7 0
3 years ago
Math question down below
mezya [45]

y=1 is the answer, there is no slope, so the formula y=mx+b turns into y=b, since 1 is the intercept 1 is b.

6 0
3 years ago
Read 2 more answers
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