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lesantik [10]
3 years ago
8

Which of the following demonstrates the commutative property across multiplication for 2 × 10 × 7        A. 2 + 10 × 7   B. 2 ×

(10 × 7)   C. 10 ×7 × 2   D. (2 × 10) × 7
Mathematics
2 answers:
Yuliya22 [10]3 years ago
3 0

The correct answer is C. 10×7×2

jolli1 [7]3 years ago
3 0

Answer:

Option C is correct

10 \times 7 \times 2

Step-by-step explanation:

Commutative property of multiplication states that you can multiply number in any order.

For example:

2 \times 3  = 3 \times 2

3 \times 4 \times 5 = 4 \times 5 \times 2

Given that:

2 × 10 × 7

By definition Commutative property of multiplication,

⇒10 \times 7 \times 2

Therefore, 10 \times 7 \times 2 demonstrates the commutative property across multiplication for 2 × 10 × 7

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The distance AND midpoint between M (-2,5) and p (7,-3)
zhannawk [14.2K]

Answer:

Distance: 12.04159458 or 12.0

Midpoint: (2.5, 1)

Step-by-step explanation:

I used the Distance and the Midpoint Formulas.



3 0
3 years ago
I need help with Math ASAP plz!!
True [87]

Answer:

x = (74-28)/2

Step-by-step explanation:

We find the perimeter of a triangle by adding the sides together

s1 +s2+s3 = P

The perimeter is 74

s1 +s2+s3 = 74

We know one of the sides is 28

28 +s2+s3 = 74

The other two sides are equal in length, call them x

28 +x+x = 74

Combine like terms

28+2x = 74

We want to solve for x

Subtract 28 from each side

28-28+2x = 74-28

2x = 74-28

Divide each side by 2

2x/2 = (74-28)/2

x = (74-28)/2

4 0
3 years ago
What's the operation for 2(t+1)=10
fiasKO [112]
The answer is t=4 hope it right
3 0
3 years ago
Cody and his friends started playing a game at 6:30 p.M. It took them it took them 47 minutes to finish the game at what time di
zaharov [31]

Answer:

7:17 PM

Step-by-step explanation:

Add another 30 minutes to 6:30 = 7:00 PM

    47-30 = 17

add the remaining 17 minutes to 7:00 = 7:17 PM

7 0
3 years ago
Given a pre-image and an image, explain how you could use transformation to show they are congruent?
JulsSmile [24]
Given a pre-image, you could use any single reflection, rotation, or translation, or combination of these transformations to re-position the pre-image on top of the image to confirm congruence.  You would be able to visually see corresponding side lengths and corresponding angles measures are the same.
8 0
3 years ago
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