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Lesechka [4]
2 years ago
8

Elina and Gustavo leave Cayley H.S. at 3:00 p.m. Elina runs north at a constant speed

Mathematics
1 answer:
Andrej [43]2 years ago
8 0

Answer:

the answer to your question is 'b'

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The function C(x)=17.5x-10 represents the cost (in dollars) of buying x tickets to the orchestra with a $10 coupon. How much doe
Rudiy27

Answer:

8 tickets

Step-by-step explanation:

x = 10 in the given equation.

We have then:

C (x) = 17.5x - 10

C (10) = 17.5 * (10) - 10

C (10) = 165

Answer:

to buy 10 tickets cost:

$ 165

b. How many tickets can you buy with $ 130?  

For this case we must make the substitution: C (x) = 130

We have then:

C (x) = 17.5x - 10

130 = 17.5x - 10

Clearing x we have:

17.5x = 130 + 10

17.5x = 140

x = (140) / (17.5)

x = 8

Answer:

You can buy 8 tickets with $ 130

5 0
2 years ago
HELPPP only got 43 minutes to answer questions
irga5000 [103]

Answer:

20 feet below sea level

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Please solve quickly
Lilit [14]
6/9 .. z. Z. Z. Z. Z. Z.
3 0
3 years ago
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
1 year ago
What is the value of x
ra1l [238]

Answer:

The value of x is dependant on the value of y.

Step-by-step explanation:

y = (number)x + (another number)

I need a PNG or  picture to give you a factual answer to the value of X.

3 0
2 years ago
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