3x+50=6x-10
subtract 3x
50=3x-10
add 10
60=3x
divide by 3
20=x
Let $x be invested in the account that paid 5% simple interest.
Let $y be invested in the account that paid 10% simple interest.
The total invested is $10,000, therefore
x + y = 10000 (1)
The interest amounts earned are respectively
x*1*0.06 = 0.06x
y*1*0.10 = 0.10y
The total interest earned is $760, therefore
0.06x + 0.10y = 760
Multiply through by 10 to obtain
0.6x + y = 7600 (2)
Subtract (2) from (1).
x + y - (0.6x + y) = 10000 - 7600
0.4x = 2400
x = $6,000
From )1), obtain
y = 10000 - 6000 = $4,000
Answer:
$6,000 in the account paying 6% simple interest, and
$4,000 in the account paying 10% simple interest.
Answer:
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Step-by-step explanation:
