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telo118 [61]
3 years ago
7

What is 9/11*4/15 in the simplest form

Mathematics
2 answers:
stiks02 [169]3 years ago
4 0

Answer:

\frac{12}{55}

Step-by-step explanation:

\frac{9}{11} × \frac{4}{15}

\frac{3}{11} × \frac{4}{5}

\frac{12}{55} Answer

Hope this helps!

Alex_Xolod [135]3 years ago
3 0
Your answer is 12/55 hope this helps :)
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Solve using Substitution<br> y = -1x - 5<br> 4x - 8y = 4
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Answers:

Step-by-step explanations:

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4 years ago
Find the equation of the line passing through the points (3,-2) and (4,6) in slope intercept form.​
noname [10]

Hey!

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They already give us the slope, so we can solve the y-intercept.

We can use (3, -2).

y = 8x + b

-2 = 8(3) + b

-2 = 24 + b

-2 - 24 = 24 + b - 24

-26 = b

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Hence, the answer is \Large\boxed{\mathsf{y~=~8x~+~-26}}

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4 years ago
The following list gives the number of pets for each of 9 students.
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2,2,2

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7 0
3 years ago
The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.​
melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

  • The common ratio is: \mathbf{r = \frac{a + 5d}{a + d}}
  • The general term of the GP is: \mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

The nth term of an AP is:

\mathbf{T_n = a + (n - 1)d}

So, the <em>2nd, 6th and 8th terms </em>of the AP are:

\mathbf{T_2 = a + d}

\mathbf{T_6 = a + 5d}

\mathbf{T_8 = a + 7d}

The <em>first, second and third terms </em>of the GP would be:

\mathbf{a_1 = a + d}

\mathbf{a_2 = a + 5d}

\mathbf{a_3 = a + 7d}

The common ratio (r) is calculated as:

\mathbf{r = \frac{a_2}{a_1}}

This gives

\mathbf{r = \frac{a + 5d}{a + d}}

The nth term of a GP is calculated using:

\mathbf{a_n = a_1r^{n-1}}

So, we have:

\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

6 0
3 years ago
What is 3d + 8 = 2d - 17 its a equation
maksim [4K]
3d+8=2d-17
-2d -2d
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d+8=-17
-8 -8
__________
d=-25
8 0
3 years ago
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