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3 years ago

11

Absolute value means the distance from zero.

1 answer:

postnew [5]3 years ago

4 0

False!! Distance is NEVER negative!!

Hope this helps!!

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A deposit of 4000 at 9.5% for 270 days

Lapatulllka [165]

The deposit is 4,000 so P = 4000.

The interest rate is 9.5%

9.5 ÷ 100 = 0.095.

r = 0.095: I = P*r*t*: I = P*r*tl = 4000*0.095*

(270/365)I = 281.095890410959 I = 281.10

So your answer would be: 281.10

8 0

3 years ago

Which equation represents a line that passes through 4 6) and is parallel to the line whose equation is 3x - 4y= 6

Pachacha [2.7K]

Parallel means their slopes should equal to each other.

Thus we need to find the slope of the given line ,

Let's do it.....

$3x - 4y = 6$

Subtract sides -3x

$- 3x + 3x - 4y = - 3x + 6$

$- 4y = - 3x + 6$

Divided sides by -4

$\frac{ - 4}{ - 4}y = \frac{ - 3}{ - 4}x + \frac{6}{ - 4} \\$

$y = \frac{3}{4}x - \frac{3}{2} \\$

This is the slope-intercept of the line.

We know that the coefficient of the x in slope-intercept form , is the slope of the line.

Thus the slope of the equation which we want is :

$slope = \frac{3}{4} \\$

_________________________________

We have following equation to find the point-slope form of the linear functions.

$y - y(given \: point) = slope \times (x - x(g \: p) \: ) \\$

Now just need to put the slope and the given point in the above equation.

$y - 6 = \frac{3}{4} \times (x - 4) \\$

Multiply sides by 4

$4(y - 6) = 3(x - 4)$

$4y - 24 = 3x - 12$

Plus sides 24

$4y - 24 + 24 = 3x - 12 + 24$

$4y = 3x + 12$

Subtract sides -3x

$4y - 3x = 3x - 3x + 12$

$4y - 3x = 12$

And we're done....♥️♥️♥️♥️♥️

4 0

3 years ago

Convert 2/5 to per cent

kozerog [31]

Answer:

40%

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the answer?

taurus [48]

$x^2y^3(1-x^3y)$

This is because you can at most, factor out x² and y³

5 0

4 years ago

Help please! (no one was answering it in physics and i really need help)

aivan3 [116]

Let $v_0$ be the cat's speed just as it leaves the edge of the table. Then taking the point 1.3 m below the edge of the table to be the origin, the cat's horizontal position at time $t$ is given by

$x(t)=v_0t$

and its height is

$y(t)=1.3\,\mathrm m-gt^2$

where $g$ is 9.8 m/s^2, the magnitude of the acceleration due to gravity.

The time it takes for the cat to hit the ground is $t$ with

$0=1.3\,\mathrm m-gt^2\implies t=\sqrt{\dfrac{1.3\,\rm m}g}\approx0.36\,\mathrm s$

(Unfortunately, this doesn't match any of the given options...)

The cat lands 0.75 m away (horizontally) from the edge of the table, so that its speed $v_0$ was

$0.75\,\mathrm m=v_0(0.36\,\mathrm s)\implies v_0\approx2.08\dfrac{\rm m}{\rm s}$

(Again, not one of the answer choices...)

I'm guessing there's either a typo in the question or answers.

6 0

3 years ago