Answer:
7
Step-by-step explanation:
Since ABCD is a parallelogram
Then AD//BC
Then:
Answer: 30
Explanation: To find the least common multiple of <em>lcm</em> of 5 and 6, we begin by listing the first few multiples of each number.
<em><u>Multiples of 5</u></em>
1 x 5 = 5
2 x 5 = 10
3 x 5 = 15
4 x 5 = 20
5 x 5 = 25
6 x 5 = 30
Notice that we skipped 0 x 6 in our list of multiples. That's because 0 x 6 is 0 and our least common multiple can't be 0.
Next we list the multiples of 6. When we list the multiples of 6, it's a good idea to keep an eye on the list of multiples for 6 so that we know when we have found a least common multiple.
<u><em>Multiples of 6</em></u>
1 x 6 = 6
2 x 6 = 12
3 x 6 = 18
4 x 6 = 24
5 x 6 = 30
Notice that 30 appears in both lists so we can stop here.
This means that the least common multiple of 5 and 6 is 30.
Answer:
This is <u>7.408 kilometres</u> far.
Step-by-step explanation:
Given:
A ship's mast is sighted just over the horizon at 4 nautical miles.
Now, to find the distance in kilometers.
As, given ship's mast is sighted just over the horizon at 4 nautical miles.
So, by using conversion factor we get the nautical mile into kilometers:
<em>1 nautical mile = 1.852 kilometer.</em>
<em>Thus, 4 nautical miles</em>
= 
= 
Therefore, this is 7.408 kilometres far.
Answer:
See below
Step-by-step explanation:
<u>Given:</u>
- f(x)= { 3x+1, if −9 < x ≤ −2
- f(x)= {−5, if. −2 < x ≤ 1
- f(x)= { x−6, if 1 < x < 7
<u>Combination of domain for the function is the following union:</u>
- (-9, 2]∪ (-2, 1]∪(1, 7) = (-9, 7)
<u>Group of answer choices:</u>
The domain is the depth interval (−26, 1).
- incorrect as (-26, -9) interval is not covered in given function
The domain is the depth interval (−9, 1].
The domain is the set of times −9 < x < −2, −2 < x < 1, and 1 < x < 7.
- incorrect as doesn't include x = -2 and x = 1
The domain is the time interval (−9, 7).
- This is correct as it is same with the domain set we got above.
