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Papessa [141]
3 years ago
5

Solve for 3(2d −1)≥4(2d−3)−3

Mathematics
1 answer:
katovenus [111]3 years ago
8 0

Answer:

6>d

Step-by-step explanation:

6d-3> 8d-12-3

6d-3>8d-15/ +15

6d+12>8d/-6d

12>2d/÷2

6>d

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6(5x/3 -4/3 - 2)= 6 (3 - 6x/6 +4/6)
sergey [27]

Answer:

21/8x

Step-by-step explanation:

10x -20 = -6x+22

+6x-20 = 22

16x-20 = 22

16x +20= +20

16x/16x = 42/16x

x = 21/8x

8 0
3 years ago
Pay as you go Pay only $6 each time you work out Regular Deal Pay $50 a month and $2 each time you work out All-in-one price! Pa
Cloud [144]

Answer:

Regular Deal

Step-by-step explanation:

<em>Pay as you go</em>

Pay only $6 each time you work out

<em>Regular Deal</em>

Pay $50 a month and $2 each time you work out

<em>All-in-one price! </em>

Pay just $100 per month for unlimited use of our great facilities

1. Carlo thinks he will go to the gym about 20 times a month. Which of these options is the least expensive for Carlo? Show how you determined your answer.​

For 20 visits to the gym:

<em></em>

<em>Pay as you go:</em>

20 × $6 = $120

<em>Regular Deal</em>

$50 + 20 × $2 = $50 + $40 = $90

<em>All-in-one price! </em>

$100

<u><em>Answer:</em></u>

The best deal is for 20 visits per month is: <em>Regular Deal</em>

7 0
2 years ago
What will the answer be
PSYCHO15rus [73]
Since 1 is your initial value you plot a point at (0,1) just like you did , but since your slope (rise/run) is 3, you will go up 3 and over 1, so you will need to graph the point (1,4) instead of (1,-2). Your line will be going up , since a graph is read left to right, you have a positive slope so your line will go up. Hope I helped !
8 0
3 years ago
Read 2 more answers
Simplify the expression \[\frac{6}{\sqrt{36} + \sqrt{27}} + \frac{6}{\sqrt{27} + \sqrt{18}} + \frac{6}{\sqrt{18} + \sqrt{9}}.\]
Viktor [21]

Answer:

= 18 ( 3 + 2(\sqrt{3}  + \sqrt{2} ))

Step-by-step explanation:

6(\sqrt{36} +\sqrt{27}) + 6(\sqrt{27} +\sqrt{18}) + 6(\sqrt{18} + \sqrt{9} )\\= 6( {6} +\sqrt{9*3}) + 6( \sqrt{9*3}  +\sqrt{9*2}) + 6(\sqrt{9*2} + 3 )\\= 6( {6} +3\sqrt{3}) + 6(3\sqrt{3} +3\sqrt{2}) + 6(3\sqrt{2} + 3 )\\=36 + 18\sqrt{3} + 18\sqrt{3} + 18\sqrt{2}+ 18\sqrt{2} + 18\\= 36+18  +18( \sqrt{3}+ \sqrt{3} +\sqrt{2} + \sqrt{2})\\= 54 + 18 (2\sqrt{3} +2\sqrt{2})\\=54 + 36\sqrt{3}  + 36\sqrt{2}\\= 18 ( 3 + 2(\sqrt{3}  + \sqrt{2} ))

7 0
3 years ago
0 ÷ 0 = 1
TEA [102]

Answer:

0/0 = undefined not 1

Step-by-step explanation: Undefined means there are no solutions possible for the operations in view. The example in question is itself wrong. n/0 is infinite but not undefined. 0/0 is undefined

7 0
2 years ago
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