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2 years ago

Help me pleaseee

Mathematics

1 answer:

Ronch [10]2 years ago

4 0

Answer:

((2•(x4))-(3•(x3)))-2x2 = 0

STEP

Equation at the end of step

((2 • (x4)) - 3x3) - 2x2 = 0

STEP

Equation at the end of step

(2x4 - 3x3) - 2x2 = 0

STEP

Pulling out like terms

5.1 Pull out like factors :

2x4 - 3x3 - 2x2 = x2 • (2x2 - 3x - 2)

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Please helps thank you

LUCKY_DIMON [66]

The best answer would be C.

Hope this helps:)

3 0

3 years ago

If f(x)=X-3/x and g(x) = 5x – 4, what is the domain of (fog)(x)?<br><br><br> NEED HELP FAST!!

dedylja [7]

Answer:

Step-by-step explanation:

This is function composition. We will take the g function and plug it into the f function wherever we see an x. That will look like this when it's done but before it's simplified:

$f(g(x))=\frac{5x-4-3}{5x-4}$ and that can be simplified down to

$f(g(x))=\frac{5x-7}{5x-4}$

The domain of this function will be all real numbers EXCEPT for the one(s) that cause the denominator to become undefined. Set the denominator equal to 0 and solve for x:

5x - 4 = 0 so

5x = 4 and

x = 4/5

In other words, D = {x | x ≠ 4/5}

6 0

3 years ago

For the set of points below determine if they are function . Then determine the domain and range. (-6,4),(5,2),(-7,-3),(0,-1),(6

Firlakuza [10]

It is a function because your output is not repeating and the (x) is your domain (y) is your range

8 0

3 years ago

Given the following absolute value function find the range f(x)= |x+5|-8

Flauer [41]

The minimum value for |x+5| is 0, so the minimum for f(x) is 0-8=-8.
There is no maximum for |x+5|, so neither does f(x).
Therefore the range of f(x)=|x+5|-8 is [-8,+inf) in interval notation, or
from -8 to infinity in words.

3 0

3 years ago

Please Assist Me With This

natka813 [3]

Answer:

(16 - 8 × 2 ÷ 4 + 6) ÷ 3 = 6

Step-by-step explanation:

The given expression is (16 - 8 × 2 ÷ 4 + 6) ÷ 3

We will solve this expression by using BODMAS rule,

B - Bracket (Parenthesis)

O - Order (exponents)

D - Division

M - Multiplication

A - Addition

S - Subtraction

(16 - $8^{1}$ × 2 ÷ 4 + 6) ÷ 3

We will solve the expression inside the parenthesis first followed up by the exponents,

(16 - $8^{1}$ × 2 ÷ 4 + 6)

= (16 - 8 × 2 ÷ 4 + 6)

Then Divide,

= (16 - 8 × $\frac{1}{2}$ + 6)

Then multiply,

= (16 - 4 + 6)

Further addition,

= (22 - 4 )

At last subtract,

= (18)

Now put the solution of the parentheses in the expression,

= (18) ÷ 3

= 6

Therefore, solution of the given expression will be 6.

7 0

3 years ago