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grin007 [14]
4 years ago
10

Two friends washed 18 cars in 2 hours. then they worked more slowly and washed 2 cars fewer per hour. how many cars did they was

h each hour at the new slower rate?
pls help idk how to solve it​
Mathematics
1 answer:
Svetradugi [14.3K]4 years ago
3 0

Answer:

They washed 18 cars in 2 hours, and each hour they washed 2 fewer.

16 cars in 4 hours,

14 cars in 6 hours,

12 in  8 hours, etc.

Step-by-step explanation:

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In point form (3,-2)
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3 years ago
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Chen is bringing fruit and veggies to serve at an afternoon meeting. He spends a total of $28.70 on 5 pints of cut veggies and 7
ololo11 [35]
Given:
total cost : 28.70
cost per pint of fruit : 2.85

Formula: 
5v + 7f = 28.70
5v + 7(2.85) = 28.70
5v + 19.95 = 28.70
5v = 28.70 - 19.95
5v = 8.75
5v/5 = 8.75/5

v = 1.75  cost per pint of veggies.

to check:
v = 1.75 ; f = 2.85 ; total cost = 28.70

5v + 7f = 28.70
5(1.75) + 7(2.85) = 28.70
8.75 + 19.95 = 28.70
28.70 = 28.70
7 0
3 years ago
The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean 1263 and a stan
DENIUS [597]

Answer:

(a) The 29th percentile for the number of chocolate chips in a bag is 1198.65.

(b) The number of chocolate chips in a bag that make up the middle 95​% of bags are [1146, 1380].

(c) The inter-quartile range of the number of chocolate chips in a bag of chocolate chip​ cookies is 157.83.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of chocolate chips in a bag of chocolate chip cookies.

The random variable <em>X</em> is normally distributed with mean, <em>μ </em>= 1263 and a standard deviation, <em>σ </em>= 117.

(a)

Compute the 29th percentile for the number of chocolate chips in a bag as follows:

P (X < x) = 0.29

⇒ P (Z < z) = 0.29

The value of <em>z</em> for the above probability is, <em>z</em> = -0.55.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sogma}\\-0.55=\frac{x-1263}{117}\\x=1263-(117\times 0.55)\\x=1198.65

Thus, the 29th percentile for the number of chocolate chips in a bag is 1198.65.

(b)

According to the Empirical rule 95% of the normally distributed data lies within 2 standard deviations of the mean.

P (μ - σ < X < μ + σ) = 0.95

P (1263 - 117 < X < 1263 + 117) = 0.95

P (1146 < X < 1380) = 0.95

Thus, the number of chocolate chips in a bag that make up the middle 95​% of bags are [1146, 1380].

(c)

The inter-quartile range of the normal distribution is:

IQR = 1.349 <em>σ</em>

Compute the inter-quartile range of the number of chocolate chips in a bag of chocolate chip​ cookies as follows:

IQR = 1.349 <em>σ</em>

      = 1.349 × 117

      = 157.833

Thus, the inter-quartile range of the number of chocolate chips in a bag of chocolate chip​ cookies is 157.83.

5 0
4 years ago
Find the area of the triangle given below.
Nimfa-mama [501]

<u>Given:</u>

A triangle with a base length of 22 ft and a height of 20 ft.

<u>To find:</u>

The area of the given triangle.

<u>Solution:</u>

The area of a triangle is obtained by multiplying \frac{1}{2} with its base length and its height.

The area of a triangle = \frac{1}{2} (b)(h).

The height is the distance from the base to the highest point on the triangle and the length of the base is the base length.

The given triangle has a base length of 22 ft and a height of 20 ft.

The area of the triangle = \frac{1}{2} (b)(h) = \frac{1}{2} (22)(20).

\frac{1}{2} (22)(20) = \frac{1}{2} (440) = 220 ft².

The given triangle has an area of 220 ft².

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4 years ago
Solve 9 ÷ 2/8. Type your answer fast please
Nutka1998 [239]

Answer:

36

Step-by-step explanation:

the answer is 36.......

4 0
3 years ago
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