Answer:
The P-value for this test is P=0.2415.
Step-by-step explanation:
We have to perform an hypothesis testing on the mean of alla account balances.
The claim is that the mean of all account balances is significantly greater than $1,150.
Then, the null and alternative hypothesis are:

The sample size is n=20, with a sample mean is 110 and standard deviation is 125.
We can calculate the t-statistic as:

The degrees of freedom fot this test are:

For this one-tailed test and 19 degrees of freedom, the P-value is:

Answer:
"Decrease of 60 dollars"
Step-by-step explanation:
<u>Sales</u>
Monday = 2000
Tuesday = 10% less = 2000*0.9 = 1800
Wednesday = 20% less = 1800 (0.8) = 1440
Thursday =
25% of Monday = 25% * 2000 = 500
Sales increased by 500 on Thursday compared to Wednesday. So Sales were:
1440 + 500 = 1940
So, compared to Monday (2000) , thursday's sales was $60 less
G = 1.25m + 5
n = 1.50n + 1
g = n
1.25m + 5 = 1.50m + 1 <== ur equation
5 - 1 = 1.50m - 1.25m
4 = 0.25m
4 / 0.25 = m
16 = m <== mary has 16 <==
g = 1.25m + 5....g = 1.25(16) + 5....g = 25 <==Gracie has 25 <==
n = 1.50m + 1...n = 1.50(16) + 1.....n = 25 <==Nancy has 25 <==
By multiplying the two numbers when u multiply pretend like the decimals are not there then when u are done the answer has to match the divisor hope it helped