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salantis [7]
3 years ago
6

Find the area of the triangle given below.

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
5 0

<u>Given:</u>

A triangle with a base length of 22 ft and a height of 20 ft.

<u>To find:</u>

The area of the given triangle.

<u>Solution:</u>

The area of a triangle is obtained by multiplying \frac{1}{2} with its base length and its height.

The area of a triangle = \frac{1}{2} (b)(h).

The height is the distance from the base to the highest point on the triangle and the length of the base is the base length.

The given triangle has a base length of 22 ft and a height of 20 ft.

The area of the triangle = \frac{1}{2} (b)(h) = \frac{1}{2} (22)(20).

\frac{1}{2} (22)(20) = \frac{1}{2} (440) = 220 ft².

The given triangle has an area of 220 ft².

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Please help this is important for me.
Anit [1.1K]
<h3>Answer: point Q is located at (-1, 1)</h3>

=================================================

Explanation:

Check out the diagram below.

Plot R(-3,7) and T(3,-11) on the same xy grid.

Draw a vertical line through R and a horizontal line through T. A right triangle forms. At the intersection point is point S(-3,-11)

----------------------

Now measure the distance from point S to point T. You can count out the spaces or subtract the x coordinates and use absolute value.

|x1-x2| = |-3-3| = |-6| = 6

From point S to point T is 6 units.

We want to subdivide this horizontal length in the ratio 1:2

What this means is that we want to plot a point U somewhere such that SU:UT = 1:2

In other words,

SU = x

UT = 2x

SU+UT = ST

x+2x = 6

3x = 6

x = 6/3

x = 2

So we must move 2 spaces to the right from point S to get to U(-1,-11)

Going from point U(-1,-11) to T(3,-11) is 4 spaces

We have SU:UT = 2:4 = 1:2 to help confirm we have the correct location for point U

From point U, we then move straight up to the line segment RT

We'll land on Q(-1,1)

----------------------

Another way to find the y coordinate of point Q is to subdivide the segment RS into the ratio 1:2 similar to how we divided ST up

Segment RS is 18 units long since we go from y = 7 to y = -11 when going from R to S.

If V was on segment RS such that

RV:VS = 1:2

and RV = y

then

RV+VS = RS

y+2y = 18

3y = 18

y = 6

RV = y = 6

VS = 2y = 2*6 = 12

So you'll move 6 units down from y = 7 to land on y = 1 (when going from the y coordinate of R to the y coordinate of Q)

3 0
3 years ago
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