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3 years ago

6.

Mathematics

1 answer:

abruzzese [7]3 years ago

7 0

Answer:

10.50

Step-by-step explanation:

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Why equals 2X plus 7Y equals 5X +4 graph the answer

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You can graph the answer on cymath.com

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2 years ago

A jumper in the long-jump goes into the jump with a speed of 12 m/s at an angle of 20° above the horizontal. How far does the ju

weeeeeb [17]

Answer:

x = 9.5 m

Step-by-step explanation:

Given:

This problem is based on 2D motion kinematics equations:

$V_0 = 12 m/s$

$\theta = 20^0$

$g=9.8 m/s^2$

At maximum height:

$V_y = 0$

Components of initial velocity:

$V_0x = V_0 cos (\theta) =(12 )(cos (20^0)) = 11.3 m/s$

$V_0x = V_0 sin (\theta) = (12)(sin (20^0)) = 4.10 m/s$

To find time to reach maximum height:

$V_y = V_0y -gt$

Plugging in the known values:

0 = 4.10 - 9.8t

$t = \frac{-4.10}{-9.8}$

$t = 0.418 s$

Total time = 2t = 2(0.418) = 0.836 s

to find horizontal distance covered:

$x = (V_0x)(t)\\x = (11.3)(0.836)\\x = 9.5 m$

8 0

3 years ago

odd function f(x) is defined for all real values of x. for the function g(x)=2.3+f(x-9), calculate g(6)+g(8)+g(10)+h(12).

PilotLPTM [1.2K]

Answer:

easy theanswer is -14x

Step-by-step explanation:

4 0

2 years ago

Write as a product: 25a2−0.01b10

Yakvenalex [24]

Answer:

We conclude that:

$25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)$

Step-by-step explanation:

Given the expression

$25a^2-0.01b^{10}$

Rewrite $25a^2-0.01b^{10}$ as $\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2$

$25a^2-0.01b^{10}=\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2$

Apply difference of two squares formulas:

$x^2-y^2=\left(x+y\right)\left(x-y\right)$

$\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2=\left(5a+\sqrt{0.01}b^5\right)\left(5a-\sqrt{0.01}b^5\right)$

$=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)$ ∵ $\sqrt{0.01}=0.1$ ,

Therefore, we conclude that:

$25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)$

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2 years ago

Simplify the expression -2d-3+8d

shepuryov [24]

Answer:

6d-3

Step-by-step explanation:

4 0

2 years ago

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