1. V = lwh
V = (8)(4)(5)
V = (32)(5)
V = 160 units³
2. V = lwh + lwh
V = (4)(2)(1) + (3)(1)(1)
V = (8)(1) + (3)(1)
V = 8 + 3
V = 11 units³
3. V = leh + s³
V = (9)(3)(4) + (3)³
V = (27)(4) + 27
V = 108 + 27
V = 135 units³
4. V = lwh
V = (3)(7)(2)
V = (21)(2)
V = 42 units³
Answer:
The area of the label is 
Step-by-step explanation:
step 1
Find the radius
we know that
The volume of the cylinder (can of tuna) is equal to
In this problem we have
substitute and solve for r
Simplify
step 2
<em>Find the lateral area of the can</em>
The lateral area of the cylinder (can of tuna) is equal to
we have
Answer:
A. The reflection preserves the side lengths and angles of triangle . The dilation preserves angles but not side lengths.
Step-by-step explanation:
Reflection is a rigid transformation. It preserves both angles and side lengths. Dilation preserves angles, but changes all lengths by the same scale factor.
<h3>Application</h3>
The described triangle was subject to reflection, which preserves angles and lengths. It was also subject to dilation, which preserves angles, but not lengths.
The appropriate description is that of choice A.
Answer:
2.5cm^2
Step-by-step explanation:
so diameter is basically radius*2...to find radius(since area of circle is pi*r^2 we need to divide diameter by 2)
so 1.8/2=0.9
now,
pi*0.9^2
pi*0.81
2.5 cm^2
Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r = 
= 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!
