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4 years ago

Identify an attribute of the "a" element that indicates the media type of z linked document

Mathematics

1 answer:

SCORPION-xisa [38]4 years ago

3 0

Answer:

Step-by-step explanation:

The id attribute requires a unique string to identify the element.

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Use your pointless mathematic skills to solve 9+10=21

alekssr [168]

The answer is 9+ 10=22

6 0

3 years ago

What are the dimensions of the largest 30-60-90 triangle that will fit inside a 45-45-90 triangle with leg length 14in.? Sketch

Ksivusya [100]

The triangle lengths would be 14√2, 7√2 and 7√6.

The sides of a 45-45-90 triangle can be listed as t, t and t√2. The legs are each 14, so the hypotenuse will be 14√2.

This will also be the longest side of the 30-60-90 triangle. Its sides can be listed as t, 2t and t√3. Since the hypotenuse is the longest side, we have:

2t=14√2

Dividing both sides by 2, we have:
2t/2 = 14√2/2
t = 7√2

The remaining side will be t√3:

t = 7√2
t√3 = 7√2(√3) = 7√6

5 0

3 years ago

Marlene surveyed her classmates asking them whether they prefer to vacation during spring break or summer and the type of vacati

zimovet [89]

Answer:

The answers for ed is

Step-by-step explanation:

16 and 10

8 0

3 years ago

Teen obesity:

Law Incorporation [45]

Answer:

95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].

Step-by-step explanation:

We are given that 15% of a random sample of 300 U.S. public high school students were obese.

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample % of U.S. public high school students who were obese = 15%

n = sample of U.S. public high school students = 300

p = population percentage of all U.S. public high school students

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.15-1.96 \times {\sqrt{\frac{0.15(1-0.15)}{300} } }$ , $0.15+1.96 \times {\sqrt{\frac{0.15(1-0.15)}{300} } }$ ]

= [0.110 , 0.190]

Therefore, 95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].

6 0

3 years ago

Here is a list of questions. For each question, decide if the responses will produce numerical data or categorical data and give

MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

Numerical data are majorly in digit form (i.e numbers), while a categorical data deals with grouped data. Thus some probable answers to the questions are:

1. Categorical data.

ii. Possible responses could be: English breakfast or Continental breakfast.

2. Categorical data.

ii. Possible responses could be: either by road or by air transportation

3. Numerical data.

ii. Possible responses could be: 6 or 10

4. Categorical data.

ii. Possible responses could be: snacks or soft drink

5. Numerical data.

ii. Possible responses could be: 20 minutes or 30 minutes

7 0

3 years ago

Read 2 more answers