The number of atoms present in 0.10 mol of PtCl2(NH3) is calculated using Avogadro law formula
that is
1 mole = 6.02 x10^23 atoms
what about 0.10 moles = ? atoms
= 6..02 x10 ^23 x 0.1 = 6.02 x10^22 atoms
The empirical formula CH₂ has a mass [(12 × 1) + (1 × 2)] = 14 g/mol
If the empirical formula is 14 g/mol,
and the molecular formula is ~140 g/mol
Then the multiple is = 140 g/mol ÷ 14 g/mol
= 10
Therefor the molecular formula is 10(CH₂) = <span>C</span>₁₀<span>H</span>₂₀<span> </span>
Answer:
javier applied force how this helps
You can simply subtract the atomic number from the mass number in order to find the number of neutrons.
Explanation:
According to Buoyance equation,
m = ![[m' \times \frac{1 - \frac{d_{a}}{d_{w}}}{1 - \frac{d_{a}}{d}}]](https://tex.z-dn.net/?f=%5Bm%27%20%5Ctimes%20%5Cfrac%7B1%20-%20%5Cfrac%7Bd_%7Ba%7D%7D%7Bd_%7Bw%7D%7D%7D%7B1%20-%20%5Cfrac%7Bd_%7Ba%7D%7D%7Bd%7D%7D%5D)
where, m = true mass
m' = mass read from the balance = 17.320 g
= density of air = 0.0012 g/ml
= density of the balance = 7.5 g/ml
d = density of liquid octane = 0.7025 g/ml
Now, putting all the given values into the above formula and calculate the true mass as follows.
m =
= ![[17.320 g \times \frac{1 - \frac{0.0012 g/ml}{7.5 g/ml}}{1 - \frac{0.0012 g/ml}{0.7025}}]](https://tex.z-dn.net/?f=%5B17.320%20g%20%5Ctimes%20%5Cfrac%7B1%20-%20%5Cfrac%7B0.0012%20g%2Fml%7D%7B7.5%20g%2Fml%7D%7D%7B1%20-%20%5Cfrac%7B0.0012%20g%2Fml%7D%7B0.7025%7D%7D%5D)
=
= 17.317 g
Thus, we can conclude that the true mass of octane is 17.317 g.