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pychu [463]
3 years ago
6

How many grams of HF are needed to react with 3.0 moles of Sn? *

Chemistry
1 answer:
Lostsunrise [7]3 years ago
6 0

Answer:

120g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

Sn + 2HF —> SnF2 + H2

Next, we shall determine the number of mole of HF needed to react with 3 moles of Sn.

From the balanced equation above, 1 mole of Sn reacted with 2 moles of HF.

Therefore, 3 moles of Sn will react with = 3 x 2 = 6 moles of HF.

Finally, we shall convert 6moles of HF to grams

This is illustrated below:

Number of mole of HF = 6moles

Molar Mass of HF = 1 + 19 = 20g/mol

Mass of HF =..?

Mass = number of mole x molar Mass

Mass of HF = 6 x 20

Mass of HF = 120g

Therefore, 120g of HF is needed to react with 3 moles of Sn

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If I initially have a gas at a pressure of 10.0 atm, a volume of 24.0 liters, and a temperature
Bezzdna [24]

Answer:

The new volume of gas is 25.7 L.

Explanation:

Given data:

Initial volume = 24.0 L

Initial pressure = 10.0 atm

Initial temperature = 200 K

Final temperature = 300 K

Final volume = ?

Final pressure = 14.0 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 10.0 atm × 24.0 L × 300K / 200 K × 14.0 atm

V₂ = 72000 atm .L. K / 2800 K.atm

V₂ = 25.7 L

The new volume of gas is 25.7 L.

5 0
4 years ago
Balance each reaction and write its reaction quotient, Qc:(b) SF₆(g) + SO₃(g) → SO₂F₂(g)
IceJOKER [234]

When we balance the given equation

      SF₆(g) + SO₃(g) → SO₂F₂(g)

We will get

      SF₆(g) + 2SO₃(g) → 3SO₂F₂(g)

Solution:

Balancing the given equaation

      SF₆(g) + SO₃(g) → SO₂F₂(g)

We have to balance the given number of O

      SF₆(g) + 2SO₃(g) → 3SO₂F₂(g)

We get balanced equation

      SF₆(g) + 2SO₃(g) → 3SO₂F₂(g)

The reaction quotient will be

     Qc = [product] / [reactant]

     Qc ​= [SO₂F₂(g)] / [SF₆(g) + SO₃(g)]

To learn more click the given link

brainly.com/question/16025432

#SPJ4

4 0
2 years ago
5.943x10^24 molecules of H3PO4 will need how many grams of Mg(OH)2 in the reaction below? 3 Mg(OH)2 + 2 H3PO4 -------> 1 Mg3(
professor190 [17]

Answer:

Mass of Mg(OH)₂ required for the reaction = 863.13 g

Explanation:

3Mg(OH)₂ + 2H₃PO₄ -------> Mg₃(PO₄)₂ + 6H₂O

(5.943 x 10²⁴) molecules of H₃PO₄ is available fore reaction. Mass of Mg(OH)₂ required for reaction.

According to Avogadro's theory, 1 mole of all substances contain (6.022 × 10²³) molecules.

This can allow us find the number of moles that (5.943 x 10²⁴) molecules of H₃PO₄ represents.

1 mole = (6.022 × 10²³) molecules.

x mole = (5.943 x 10²⁴) molecules

x = (5.943 x 10²⁴) ÷ (6.022 × 10²³)

x = 9.87 moles

From the stoichiometric balance of the reaction,

2 moles of H₃PO₄ reacts with 3 moles of Mg(OH)₂

9.87 moles of H₃PO₄ will react with y moles of Mg(OH)₂

y = (3×9.87)/2 = 14.80 moles

So, 14.8 moles of Mg(OH)₂ is required for this reaction. We them convert this to mass

Mass = (number of moles) × Molar mass

Molar mass of Mg(OH)₂ = 58.3197 g/mol

Mass of Mg(OH)₂ required for the reaction

= 14.8 × 58.3197 = 863.13 g

Hope this Helps!!!

5 0
4 years ago
Read 2 more answers
How many milliners of hydrogen gas ar produced by the reaction 0.020 moles of magnesium with excess of hydrochloride acid at sto
jeyben [28]

Answer:- 448 mL of hydrogen gas are formed.

Solution:- It asks to calculate the volume of hydrogen gas formed in milliliters at STP when 0.020 moles of magnesium reacts with excess HCl acid. The balanced equation is:

Mg+2HCl\rightarrow MgCl_2+H_2(g)

There is 1:1 mol ratio between Mg and hydrogen gas. So, the moles of hydrogen gas is also equals to the moles of Mg reacted.

moles of Hydrogen gas formed = 0.020 mol

At STP, volume of 1 mol of the gas is 22.4 L. We need to calculate the volume of 0.02 moles of hydrogen gas.

0.02mol(\frac{22.4L}{1mol})

= 0.448 L

They want answer in mL. So, let's convert L to mL using the conversion formula, 1L = 1000mL

0.448L(\frac{1000mL}{1L})

= 448 mL

So, 0.020 moles of magnesium would produce 448 mL of hydrogen gas at STP on reacting with excess of HCl acid.

5 0
3 years ago
Which statements correctly describe sound ( select all that apply)
xeze [42]

Answer:

The answer is all of the above

Explanation:

Sound has waves which are compression waves and those waves transfer into energy molecules. Sound is heard by human ears. Sound waves can behave in predictable ways. All sound requires a medium through to travel

5 0
3 years ago
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