Answer:
maybe it's 9 not sure though if it's wrong sorry
Answer:
C. (1, 10) and (6, 5)
Step-by-step explanation:
To find the point with a distance of 5 units.
Let the points be x and y.
x = x1 and x2
y = y1 and y2
x2 - x1 = 5 units
y2 - y1 = 5 units.
A quick look at the options, we can tell that the correct option is C.
From points (1, 10) and (6, 5)
x1 = 1, x2 = 6, y1 = 10 and y2 = 5
Substituting into the equation above, we have;
x2 - x1 = 6 - 1 = 5 units
y2 - y1 = 5 - 10 = -5 units.
Therefore, option C with points (1,10) and (6,5) have a distance of five units between them.
It already shows that AB is 49°
in order to find ABC you must first find BC
360 - (AC + AB) = BC
360 - 156 = BC
204° = BC
NOW add BC with AB
49 + 204
253
angle ABC is 253°
now to find BAC add AB and AC
49 + 107 = 156°
angle BAC is 156°
FINALLY to find ACB add AC and CB
107 + 204
311°
angle ACB is 311°
Answer: 3x + 4y = - 26
Explanation:
1) the standard form is Ax + By = C
2) given: y + 5 = - (3 / 4) (x + 2)
3) multiply both sides by 4:
4y + 20 = - 3 (x + 2)
4) expand the parenthesis using distributive property:
4y + 20 = -3x - 6
5) transpose -3x and 20
4y + 3x = - 20 - 6
6) combine like terms
4y + 3x = - 26
7) rearrange:
3x + 4y = - 26
That is the standard form of the linear equation given.
B
Step-by-step explanation:
