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otez555 [7]
3 years ago
9

Simplify the expression. Write the answer using scientific notation. (4 x 10^13)^-2 -8 x 10^-26 6.25 x 10^-27 0.0625 x 10^-26 6.

25 x 10^-28
Mathematics
2 answers:
zimovet [89]3 years ago
6 0

Answer:

Option 4th is correct that is:6.25\cdot 10^{-28}

Step-by-step explanation:

We have been given an expression:

(4\cdot 10^{13})^{-2}

4^{-2}\cdot 10^{13\cdot -2}

Using x^{-a}=\frac{1}{x^a}

Here, x= and a= -2

\frac{1}{4^2}\cdot 10^{-26}

On simplification:

0.0625\cdot10^{-26}

When we right shift the decimal to 2 points power will be deducted by 2

6.25\cdot 10^{-28}

Therefore, Option 4th is correct that is:6.25\cdot 10^{-28}

ioda3 years ago
6 0

(4 x 10^13)^-2

(4)^-2 x (10^-26)

.0625 x 10^-26 = 6.25 x 10 ^ -28

                The underlined expression is the right answer because it follows the rule of scientific notation.

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George is considering two different investment options. The first option offers 7.4% per year simple interest on the
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Answer:

Part A: The value of the simple interest investment at the end of three years is $12,220

Part B: The value of the compounded quarterly interest investment at the end of three years is $12,134.08

Part C: The simple interest investment is better over the first three years

Part D: I advise George to invest his money in the compounded interest investment if he will keep the money for a long time

Step-by-step explanation:

Part A:

A = P + P r t, where

  • A represents the value of the investment
  • P represents the original amount
  • r represents the  rate in decimal
  • t represents the time in years

∵ George deposits $10,000

∴ P = 10,000

∵ First option offers 7.4% per year simple interest

∴ r = 7.4% = 7.4 ÷ 100 = 0.074

∵ He may not withdraw any of  the money for three years after

   the initial deposit

∴ t = 3

- Substitute all of these values in the formula above

∴ A = 10,000 + 10,000(0.074)(3)

∴ A = 10,000 + 2,220

∴ A = 12,220

The value of the simple interest investment at the end of three years is $12,220

Part B:

A=P(1+\frac{r}{n})^{nt}, where

  • A represents the value of the investment
  • P represents the original amount
  • r represents the  rate in decimal
  • n is a number of periods of a year
  • t represents the time in years

∵ George deposits $10,000

∴ P = 10,000

∵ The second option offers a 6.5% interest rate compounded quarterly

∴ r = 6.5% = 6.5 ÷ 100 = 0.065

∴ n = 4 ⇒ quarterly

∵ He may not withdraw any of  the money for three years after

   the initial deposit

∴ t = 3

- Substitute all of these values in the formula above

∴ A=10,000(1+\frac{0.065}{4})^{(4)(3)}

∴ A=10,000(1.01625)^{12}

∴ A = 12,134.08

The value of the compounded quarterly interest investment at the end of three years is $12,134.08

Part C:

∵ 12,220 > 12,134.08

∴ The simplest interest investment is better than the compounded

    interest investment at the end of three years

The simple interest investment is better over the first three years

Part D:

I advise George to invest his money in the compounded interest investment if he will keep the money for a long time

Look to the attached graph below

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  • The blue curve represents the compounded interest investment
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  • After that the blue curve is over the red line that means the compounded quarterly is better because it gives more money than the simple interest

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