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otez555 [7]
3 years ago
9

Simplify the expression. Write the answer using scientific notation. (4 x 10^13)^-2 -8 x 10^-26 6.25 x 10^-27 0.0625 x 10^-26 6.

25 x 10^-28
Mathematics
2 answers:
zimovet [89]3 years ago
6 0

Answer:

Option 4th is correct that is:6.25\cdot 10^{-28}

Step-by-step explanation:

We have been given an expression:

(4\cdot 10^{13})^{-2}

4^{-2}\cdot 10^{13\cdot -2}

Using x^{-a}=\frac{1}{x^a}

Here, x= and a= -2

\frac{1}{4^2}\cdot 10^{-26}

On simplification:

0.0625\cdot10^{-26}

When we right shift the decimal to 2 points power will be deducted by 2

6.25\cdot 10^{-28}

Therefore, Option 4th is correct that is:6.25\cdot 10^{-28}

ioda3 years ago
6 0

(4 x 10^13)^-2

(4)^-2 x (10^-26)

.0625 x 10^-26 = 6.25 x 10 ^ -28

                The underlined expression is the right answer because it follows the rule of scientific notation.

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3√2x+1=15, then what is the value of x?<br><br> 0
kifflom [539]

Answer:

x = 7√2/3

decimal = 3.299831

Step-by-step explanation:

Subtract 1 from both sides

3√2x+1-1=15-1

Simplify

3√2x=14

Divide both sides by 3√2

3√2x/3√2 = 14/3√2

Simplify

x= 7√2/3

5 0
3 years ago
Which equation is y = 9x2 + 9x – 1 rewritten in vertex form?
Anastasy [175]

Answer:

y = 9(x +\frac{1}{2}) ^ 2 -\frac{13}{4}

Step-by-step explanation:

An equation in the vertex form is written as

y = a (x-h) + k

Where the point (h, k) is the vertex of the equation.

 

For an equation in the form ax ^ 2 + bx + c the x coordinate of the vertex is defined as

x = -\frac{b}{2a}

In this case we have the equation y = 9x^2 + 9x - 1.

Where

a = 9\\\\b = 9\\\\c = -1

Then the x coordinate of the vertex is:

x = -\frac{9}{2(9)}\\\\x = -\frac{9}{18}\\\\x = -\frac{1}{2}

The y coordinate of the vertex is replacing the value of x = -\frac{1}{2} in the function

y = 9 (-0.5) ^ 2 + 9 (-0.5) -1\\\\y = -\frac{13}{4}

Then the vertex is:

(-\frac{1}{2}, -\frac{13}{4})

Therefore The encuacion excrita in the form of vertice is:

y = a(x +\frac{1}{2}) ^ 2 -\frac{13}{4}

To find the coefficient a we substitute a point that belongs to the function y = 9x^2 + 9x - 1

The point (0, -1) belongs to the function. Thus.

-1 = a(0 + \frac{1}{2}) ^ 2 -\frac{13}{4}

-1 = a(\frac{1}{4}) -\frac{13}{4}\\\\a = \frac{-1 +\frac{13}{4}}{\frac{1}{4}}\\\\a = 9

<em>Then the written function in the form of vertice is</em>

y = 9(x +\frac{1}{2}) ^ 2 -\frac{13}{4}

7 0
3 years ago
The coordinates of the preimage are: A(8,8) B(10,6) C(2,2) We want to reflect over y=−1 first. Our new coordinates are: A′(8, )
WITCHER [35]

Answer:

1)A'(8,-10), B'(10,-8), C'(2,-4)

2)A''(8,-4), B''(10,-6), C''(2,-10

Step-by-step explanation:

Given:

Points A(8,8) B(10,6) C(2,2)

reflection over y=-1

Perpendicular distance between points y-coordinates of points (A, B and C) and y=-1 are 9,7 and 3

after reflections, the perpendicular distance will be 18,14,6 and the points will be at

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Now  

Points A(8,-10), B(10,-8), C(2,-4)

reflection over y=−7

Perpendicular distance between points y-coordinates of points (A, B and C) and y=-7 are 3,1 and 3

after reflections, the perpendicular distance will be 6,2,6 and the points will be at

A''(8,-4), B''(10,-6), C''(2,-10) !

8 0
3 years ago
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