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laila [671]
3 years ago
6

There are 30 families. Two families have 4-5 pets. What percent of the families own 4-5 pets?

Mathematics
1 answer:
amm18123 years ago
3 0
2/30=0.06 repeated. 0.06=6%. 7% or 6.6% of the 30 families have 4-5 pets.
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Find p+q, given that (q+4)(p+3)-(q+2)(p+1)=44.
Fofino [41]
Q = -p + 17
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A contractor can pay his crew at most $250 a day. It costs $45 each day to operate the forklift and $60 a day for each crew memb
zzz [600]
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3.
saveliy_v [14]

Answer: -4.96x + 6

Step-by-step explanation:

In this problem, it wants you to multiply the -0.4 by the numbers in the parentheses. Don’t let the X confuse you. This is just a placeholder for an unknown number. So first you would multiply the -0.4 into the 10.2, And once you get your answer, just add the X to the end. Which is -4.08x. Then, you would do the same thing, multiply the -0.4 (the number outside of the parenthesis, only with the -15 now. Which gets you 6. Lastly, you take the -0.4 once more and multiply it by the 2.2x. Which gets you -0.88.


-0.4 (10.2x-15+2.2x)

= - 4.08x +6 -0.88x

Now that you have this problem, combined like terms. What are the like terms in this problem?

The -4.08x can be combined with the -0.88 which gets you -4.96. Bring the +6 down, and that gets you your answer of -4.96 +6.


-4.08x -0.88x +6

= -4.96x +6


This would be your final answer because nothing further can be done at this point.


hope this helps!

3 0
2 years ago
A car, originally valued at 70,000 in 2006 depreciates exponentially at a rate of 4% each year. Round the expected value of the
lora16 [44]

Answer:

$42,890

Step-by-step explanation:

The standard form for an exponential equation is

y=a(b)^x

where a is the initial amount value and b is the growth rate or decay rate and t is the time in years.  Since we are dealing with money amounts AND this is a decay problem, we can rewrite accordingly:

A(t)=a(1-r)^t

where A(t) is the amount after the depreciation occurs, r is the interest rate in decimal form, and t is the time in years.  We know the initial amount (70,000) and the interest rate (.04), but we need to figure out what t is.  If the car was bought in 2006 and we want its value in 2018, a total o 12 years has gone by.  Therefore, our equation becomes:

A(t)=70,000(1-.04)^{12} or, after some simplification:

A(t)=70,000(.96)^{12}

First rais .96 to the 12th power to get

A(t) = 70,000(.6127097573)

and then multiply.

A(t) = $42,890

8 0
3 years ago
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