C.Quadrilateral is the answer for the following because rhombus, trapezoid, isosceles trapezoid have parallel sides.
Hope you won't be turned off by a correction, but we really need to use the symbol " ^ " to denote exponentiation.
Thus, we have x^2 = 100
Taking the square root of both sides, we get x = plus or minus 10. Verify, please, that both x = -10 and x = +10 satisfy the given equation.
Hi there!
Assuming "Find the product" means multiplying (4x-3) by (3x+8) and factor to it's simplest form the answer would be:
12x²+23x-24
The way you solve this is by using the distributive property of multiplication as shown below:
Start by multiplying -3 from (4x-3) by everything in (3x+8)
3x*(-3) = -9x
8*(-3) = -24
Once you've done that you then multiply everything 4x
4x*8 = 32x
4x*3x = 12x²
(Note: when multiplying two of the same variables like x it means you are multiplying x by itself which is the same as x²)
When you put all of this together it looks like this
12x²+32x-9x-24
from there we combine like terms
32x-9x = 23x
to get
12x²+23x-24
I hope this helps!
God bless,
ASIAX
Answer:
Variance = 1,227.27
Standard deviation = 35.03
Step-by-step explanation:
To calculate these, we use the following formulas:
Mean = (sum of the values) / n
Variance = ((Σ(x - mean)^2) / (n - 1)
Standard deviation = Variance^0.5
Where;
n = number of values = 20
x = each value
Therefore, we have:
Sum of the values = 29 + 32 + 36 + 40 + 58 + 67 + 68 + 69 + 76 + 86 + 87 + 95 + 96 + 96 + 99 + 106 + 112 + 127 + 145 + 150 = 1,674
Mean = 1,674 / 20 = 83.70
Variance = ((29-83.70)^2 + (32-83.70)^2 + (36-83.70)^2 + (40-83.70)^2 + (58-83.70)^2 + (67-83.70)^2 + (68-83.70)^2 + (69-83.70)^2 + (76-83.70)^2 + (86-83.70)^2 + (87-83.70)^2 + (95-83.70)^2 + (96-83.70)^2 + (96-83.70)^2 + (99-83.70)^2 + (106-83.70)^2 + (112-83.70)^2 + (127-83.70)^2 + (145-83.70)^2 + (150-83.70)^2) / (20 - 1) = 23,318.20 / 19 = 1,227.27
Standard deviation = 1,227.27^0.5 = 35.03
G^−m ÷ g^n
1st g^−m=1/g^m, hence g^−m ÷ g^n = (1/g^m) /(g^n)==> 1/(g^m)(g^(n)
==> 1/(g^m+n) or g^(-m-n)
